Answer:
Erie to Rochester is 145 miles
Step-by-step explanation:
If we designate the points of interest as C, E, and R, we are told that ...
CE + ER = CR . . . . . the various distances are segments of a straight line
For CE = 94 and CR = 239, we can fill in the given information and solve for ER.
94 + ER = 239
ER = 239 -94 . . . . . . subtract 94 from both sides of the equation
ER = 145
The distance from Erie to Rochester is 145 miles.
It takes 4.3 seconds for the rocket to return to earth.
The equation is:

where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height. We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42. This gives us:

We will use the quadratic formula to solve this. The quadratic formula is:

Plugging in our information we have:

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
Answer:
75
Step-by-step explanation:
angle 2 and angle 6 are corresponding angles, because the lines are parallel and cut by a transversal, corresponding angles are congruent, thus if angle 2 is 75 degrees then angle 6 is 75 degrees
Answer:
x ≈ 16.52
Step-by-step explanation:
Use the tangent ratio in the right triangle to find x
tan36° =
= 
Multiply both sides by x
x × tan36° = 12 ( divide both sides by tan36° )
x = 12 / tan36° ≈ 16.52 ( to 2 dec. places )
Answer:
4/42 = 2/21 when simplified down
Step-by-step explanation:
Cancel the common factor: 2
=2/21