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swat32
3 years ago
6

A person who had $1,000,000 gave $100 to charity. How much must a student who has $100 give to charity to give proportionally th

e same as the millionaire?
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

(100 / 1,000,000) × 100% = 0.01%

x = amount of money the student has to give.

(x / 100) × 100% = 0.01%

We can cancel out the 100's

x = $0.01

The student would have to give $0.01 or 1 cent

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3 years ago
If rectangle ABCD is rotated counter clock wise 90º about the origin, what will be the coordinates of the vertex D'?
7nadin3 [17]
So, the best way to do this is translate it to clockwise. 90 degrees counterclockwise is equal to 270 degrees clockwise. So, basically, to rotate, you would follow the following format for each point-
(X,Y) -> (-Y,X)
Now, you do it for each of the points.
A= (-5,5), so A' would be (-5,-5)
B= (-1,5), so B' would be (-5,-1)
C= (-5,4), so C' would be (-4,-5)
D= (-1,4) so D' would be (-4,-1)
Notice, how all the points end up in the square below it. Each quadrant has a specific number. The top right is quadrant 1, the top left is quadrant 2, the bottom left is quadrant 3, and the bottom right is quadrant 4. If you are rotating 270 degrees clockwise, you move to the right, like a clock. That puts the new rectangle in quadrant 3. That is a way to check your work.
Now, just so you know for future reference, the following are also different formats for different problems--
A 90 degree Clockwise rotation about the origin will be (X,Y) -> (Y, -X) *Note, -x just stands for the opposite. Say your original x is a negative number. Then the prime (new) x will be positive.
A 180 degree Clockwise rotation about the origin would be (X,Y) -> (-X,-Y) *Note, -y also stands for the opposite.
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For translating---
90 degrees Clockwise = 270 degrees Counter
270 degrees Clockwise = 90 degrees Counter

Hope this helped!
4 0
3 years ago
What are all of the real roots of the following polynomial? f(x) x^4-24x^2-25
Greeley [361]

<u>Answer:</u>

x = ±5

<u>Step-by-step explanation:</u>

We are given the following polynomial function and we are to find all of its real roots:

x^4-24x^2-25

Let y=x^2 so we can now write it as:

y^2-24y-25

Factorizing it to get:

(y^2+y)+(-25y-25)

y\left(y+1\right)-25\left(y+1\right)

\left ( y + 1 \right ) \left ( y - 2 5 \right)

Substitute back y=x^2 to get:

\left ( x^2 + 1 \right ) \left ( x^2 - 25 \right )

\left ( x^2 + 1 \right ) \left ( x + 5 \right ) \left ( x - 5 \right )

The quadratic factor has only complex roots. Therefore, the real roots are x = ±5.

3 0
3 years ago
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Serhud [2]
The answer is 3 becasue 

3 0
3 years ago
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Solve −5x = 15. (1 point)<br><br><br> −3<br> 3<br> 10<br> 20
Luba_88 [7]
Remember you can do anything to an eqautoin as long as you do oit to both sides

-5x=15
try to get 1x by itself

remember
(ax)/a=x when a=a

so
-5x=15
get x
divide both sides by -5
remember to flip sign
(-5x)/(-5)=15/(-5)
x=-3

answer is first one
x=-3 

8 0
3 years ago
Read 2 more answers
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