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telo118 [61]
3 years ago
12

A cyclist maintains a constant velocity of

Physics
1 answer:
Feliz [49]3 years ago
3 0
The answer is 509 m.

Let point B be 253 m from point A. Let point C be 64 s away from point B.
Let d1 be the displacements from point A to point B and d2 and be the displacements from point B to point C
Step 1. Calculate the displacement from the point B after 64 s.
Step 2. Calculate the displacement from the point A by summing up two distances (d1 and d2).

Step 1.
v = d2/t
v = 4 m/s
d2 = ?
t = 64s
____
4 = d2/64
d2 = 64 * 4 = 256 m


Step 2:
d = d1 + d2
d1 = 253 m
d2 = 256 m
d = 253 + 256 = 509m

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a)

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E_2=9\times 10^9\times \dfrac{19\times 10^{-6}}{0.089^2}\ N/C

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b)

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E=E_1+E_2

E=268.22\times 10^{6}\ N/C

The direction will be positive direction.

   

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