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Alecsey [184]
3 years ago
14

The purpose of a fuse or circuit breaker is _____. to speed up the current to slow down the current to stop current that is flow

ing too fast to stop current that is flowing too slow
Physics
2 answers:
Papessa [141]3 years ago
8 0


Actually, the best way to put it would be if the current is too large or too small. 

Fuses and circuit breakers are both devices that "break" if the current flowing through them is too large.

A fuse is usually a thin piece of wire that will melt and break the circuit if too large a current flows through it. The thicker the fuse wire, the more the current needed to melt it and the higher the "rating" of the fuse. The function of the fuse is to protect the wiring and the equipment.

A circuit breaker is an electronic circuit that will switch off the current if it is too great. A circuit breaker is designed to operate much more quicker than a fuse and so the damage is less because the current is switched off in a much shorter time.


iogann1982 [59]3 years ago
7 0

Answer: The purpose of a fuse or circuit breaker is to stop current that is flowing too fast.

Explanation:

In case of over flowing of current carrying charges, a circuit breaker or fuse breaks the current and protects the circuit from damage. A fuse is wire having low melting point placed in a circuit. When current is moving too fast i.e. in case of over current, the heat produced melts this wire breaking the circuit. Similarly a circuit breaker is a switch which opens up in case of over flow of current.

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There is no great force, the force exerted by the Earth on the Sun, and the force exerted by the Sun on the Earth are equal

Explanation:

By definition...

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2 years ago
When monochromatic light illuminates a grating with 7000 lines per centimeter, its second order maximum is at 62.4°. what is the
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When red light illuminates a grating with 7000 lines per centimeter, its second maximum is at 62.4°. What is the wavelength of this light?

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3 years ago
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The work done to compress a spring with a force constant of 290.0 N/m a total of 12.3 mm is: a) 3.57 J b) 1.78 J c) 0.0219 J d)
iren2701 [21]

Answer:

Work done, W = 0.0219 J

Explanation:

Given that,

Force constant of the spring, k = 290 N/m

Compression in the spring, x = 12.3 mm = 0.0123 m

We need to find the work done to compress a spring. The work done in this way is given by :

W=\dfrac{1}{2}kx^2

W=\dfrac{1}{2}\times 290\times (0.0123)^2

W = 0.0219 J

So, the work done by the spring is 0.0219 joules. Hence, this is the required solution.

7 0
3 years ago
MATHPHYS HELP
rusak2 [61]

Answer:

16.4287

Explanation:

The force and displacement are related by Hooke's law:

F = kΔx

The period of oscillation of a spring/mass system is:

T = 2π√(m/k)

First, find the value of k:

F = kΔx

78 N = k (98 m)

k = 0.796 N/m

Next, find the mass of the unknown weight.

F = kΔx

m (9.8 m/s²) = (0.796 N/m) (67 m)

m = 5.44 kg

Finally, find the period.

T = 2π√(m/k)

T = 2π√(5.44 kg / 0.796 N/m)

T = 16.4287 s

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3 years ago
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Answer:

Physiological needs

Explanation:

3 0
3 years ago
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