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Alecsey [184]
3 years ago
14

The purpose of a fuse or circuit breaker is _____. to speed up the current to slow down the current to stop current that is flow

ing too fast to stop current that is flowing too slow
Physics
2 answers:
Papessa [141]3 years ago
8 0


Actually, the best way to put it would be if the current is too large or too small. 

Fuses and circuit breakers are both devices that "break" if the current flowing through them is too large.

A fuse is usually a thin piece of wire that will melt and break the circuit if too large a current flows through it. The thicker the fuse wire, the more the current needed to melt it and the higher the "rating" of the fuse. The function of the fuse is to protect the wiring and the equipment.

A circuit breaker is an electronic circuit that will switch off the current if it is too great. A circuit breaker is designed to operate much more quicker than a fuse and so the damage is less because the current is switched off in a much shorter time.


iogann1982 [59]3 years ago
7 0

Answer: The purpose of a fuse or circuit breaker is to stop current that is flowing too fast.

Explanation:

In case of over flowing of current carrying charges, a circuit breaker or fuse breaks the current and protects the circuit from damage. A fuse is wire having low melting point placed in a circuit. When current is moving too fast i.e. in case of over current, the heat produced melts this wire breaking the circuit. Similarly a circuit breaker is a switch which opens up in case of over flow of current.

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A person of mass 75 kg stands at the center of a rotating merry-go-round platform of radius 3.3 m and moment of inertia
vivado [14]

Answer:

(a) 0.426 rad/s

(b) Before 296.225 J and After 148.5 J

Explanation:

At the center of merry-go-round, the person's weight is 75 Kg with moment of inertia of 820 kgm2 and the initial angular velocity is 0.85 rad/s

At the edge, the new angular velocity gained depends on the new moment of inertia

Here, the final moment of inertia is given by Initial moment of inertia + MR^{2} where M is the mass and R is the radius of merry-go-round

Final moment of inertia=820+(75*3.3^{2})=1636.75

From the law of conservation of angular momentum as torque is zero

I_i\times\omega_1=I_f\times\omega_2  and making \omega_2 the subject then

\omega_2=\frac {I_i\times\omega}{I_f}

where I_i and I_f are initial and final moment of inertia, \omega_1 and \omega_2 are initial and final angular velocity.

Substituting the provided values

\omega_2=\frac {0.85\times 820}{1636.75}=0.425843898\approx 0.426 rad/s

(b)

Initial rotational kinetic energy is given by

0.5I_i\times \omega_1^{2}

KE_i=0.5\times 820\times 0.85^{2}=296.225 J

The final rotational kinetic energy is given by

0.5I_f\times \omega_2^{2}

KE_i=0.5\times 1636.75\times 0.426^{2}\approx 148.5 J

7 0
4 years ago
What role does the environment play in defining the appearance of an organism? 
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6 0
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The climber dropped her compass at the end of her 240-meter climb. How long did it take to strike bottom?
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240 = 0+1/2 (-9.8t

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<span>240/-4.9 = t</span><span>
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