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kolezko [41]
4 years ago
11

Goodie morning—————————what is nitric acid?​

Physics
2 answers:
Lorico [155]4 years ago
7 0

Good morning...

Nitric acid production is mainly driven by fertilizer industry. Nitric acid is used in the production of ammonium nitrate and calcium ammonium nitrate which find applications as fertilizers.

s344n2d4d5 [400]4 years ago
3 0

Answer:

Nitric acid, also known as aqua fortis and spirit of niter, is a highly corrosive mineral acid. The pure compound is colorless, but older samples tend to acquire a yellow cast due to decomposition into oxides of nitrogen and water. Most commercially available nitric acid has a concentration of 68% in water.

Explanation:

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Arrange the following parts in the order that matches the light path through a light microscope:
Nonamiya [84]
From the top downward:

Ocular lens (eyepiece)
Body tube
Objective lens
Specimen
Light source
3 0
4 years ago
Why do we consider space to be a vacuum? Predict results if the experiment were preformed in a vacuum.
stepan [7]
I don’t know if this helps your answer:


https://www.britannica.com/science/vacuum-physics

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4 0
3 years ago
A textbook of mass 2.09 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d
Nutka1998 [239]

Answer:

The tension in the part of the cord attached to the textbook is 6.58 N.

Explanation:

Given that,

Mass of textbook = 2.09 kg

Diameter = 0.190 m

Mass of hanging book = 3.08 kg

Distance = 1.26 m

Time interval = 0.800 s

Suppose,we need to calculate the tension in the part of the cord attached to the textbook

We need to calculate the acceleration

Using equation of motion

y=ut+\dfrac{1}{2}at^2

a=\dfrac{2y}{t^2}

Put the value into the formula

a=\dfrac{2\times1.26}{0.800}

a=3.15\ m/s^2

We need to calculate the tension

When the book is moving with acceleration

Using formula of tension

T=ma

T=2.09\times3.15

T=6.58\ N

Hence, The tension in the part of the cord attached to the textbook is 6.58 N.

7 0
3 years ago
A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased t
Margaret [11]

Answer:

When the pressure and the temperature are increased the volume is 285.7 ml.

Explanation:

We can find the new volume by using the Ideal Gas Law:

PV = nRT

Where:

P: is the pressure

V: is the volume

n: is the number of moles

R: is the gas constant

T: is the temperature  

Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:

nR = \frac{P_{1}V_{1}}{T_{1}}   (1)  

And finally, when P₂ = 700 torr and T₂ = 20 °C, we have:

nR = \frac{P_{2}V_{2}}{T_{2}}   (2)

By equating (1) with (2):

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}                

V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml

Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.                                                

I hope it helps you!                  

3 0
3 years ago
\nljbvjlsfhglskhg;skgh;sfjs;ojsr;ogjs;dofhs;dkhs;lifhns
vladimir1956 [14]
That is nonsense, also known as jibberish
8 0
3 years ago
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