Electrons are present in distinct energy levels around the nucleus.
Explanation:
About energy quantization at the atomic level, electrons are present in distinct energy levels around the nucleus.
This was the view from Bohr's model of the atom based on the quantum mechanics.
- His model was based on the premise that electrons can move round the nucleus only in permissible orbits or energy levels.
- An electron in an energy level has a definite amount of energy associated with it at that level.
- For electrons to undergo transition from one level to another, they gain or lose energy.
- This is the concept of the energy quantization of atomic level.
Learn more:
Neil Bohr brainly.com/question/4986277
#learnwithBrainly
Answer:
118 mL
Explanation:
We can easily calculate the final volume of the solution (V₂) by applying the following mathematical expression:
V₁ x C₁ = V₂ x C₂
⇒ V₂ = V₁ x C₁/C₂
Given:
V₁ = 10 mL
C₁ = 0.65 M
C₂ = 0.055 M
We replace the data in the mathematical expression to calculate V₂:
V₂ = V₁ x C₁/C₂ = 10 ml x (0.65 M)/ (0.055 M) = 118.18 mL ≅ 118 mL
Key Points
For many solids dissolved in liquid water, the solubility increases with temperature.
The increase in kinetic energy that comes with higher temperatures allows the solvent molecules to more effectively break apart the solute molecules that are held together by intermolecular attractions.
Explanation:
The answer is
153.7
k
J
.
What you are asked to determine is the total energy required to go from ice to water, and then from water to vapor - the phase changes underwent by the water molecules.
In order to do this, you'll need to know:
Heat of fusion of water:
Δ
H
f
=
334
J
/
g
;
Heat of fusion vaporization of water:
Δ
H
v
=
2257
J
/
g
;
Specific heat of ice:
c
=
2.09
J
/
g
∘
C
;
Specific heat of water:
c
=
4.18
J
/
g
∘
C
;
Specific heat of steam:
c
=
2.09
J
/
g
∘
C
;
So, the following steps describe the overall process:
1. Determine the heat required to raise the temperature of the ice from
−
15.0
∘
C
to
0
∘
C
:
q
1
=
m
⋅
c
i
c
e
⋅
Δ
T
=
50.0
g
⋅
2.09
J
g
⋅
∘
C
⋅
(
0
∘
C
−
(
−
15
∘
C
)
)
=
1567.5
J
2. Determine the heat required to convert
0
∘
C
ice to
0
∘
C
water:
q
2
=
m
⋅
Δ
H
f
=
50.0
g
⋅
334
J
g
=
16700
J
3. Determine the heat required to go from water at
0
∘
C
to water at
100
∘
C
:
Hey mate
SORTING METHOD can easily be used to separate a mixture of steel ball bearing and marbles. This separation method is suitable because the two substances that are mixed together have big sizes, so it is easy to separate the two by hand picking the particles. Sorting method is usually used as a separation technique when the size of the mixture is big and the mixed substances are in the same state.
Hope it help ya