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Katyanochek1 [597]

3 years ago

11

How do you determine the minimum horizontal velocity

1 answer:

yaroslaw [1]3 years ago

6 0

Divide displacement by time

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If the pitch of the sound coming out of a speaker increases, which statement is true about the sound wave?

S_A_V [24]

Answer:

frequency and amplitude increases

3 0

2 years ago

Monitoring cash flow and keeping track of the bottom line of a business are responsibilities for whom?

lina2011 [118]

Answer:
A financial manager.

Explanation:
This is because a financial manager oversees the financial operations of a company. Generally, a financial manager assumes accounting responsibilities for the company. A financial manager is responsible for planning and managing the company's financial resources.

Side note:
Hope this helps!
Please give Brainliest!

6 0

3 years ago

You throw a bouncy rubber ball and a wet lump of clay, both of mass m, at a wall. Both strike the wall at speed v, but while the

lana [24]

Answer:

<em>The fifth option is the correct answer: mv; 2 mv</em>

Explanation:

<u>Change of Momentum</u>

Assume an object has a momentum p1 and after some interaction it now has a momentum p2, the change of momentum is

$\Delta p=p_2-p_1$

The momentum is computed as

$p=mv$

Where m is the mass of the object and v its speed. Now let's analyze the situation of both the ball and the clay.

The clay has an initial speed v and a mass m, thus its initial momentum is

$p_1=mv$

When it hits the wall, it sticks, thus its final speed is 0 and

$p_2=0$

The change of momentum is

$\Delta p=0-mv=-mv$

The absolute change is mv

Now for the ball, the initial condition is the same as it was for the clay, but the ball hits back at the same speed, thus its final momentum is

$p_2=-mv$

The change of momentum is

$\Delta p=-mv-mv=-2mv$

The absolute change is 2mv

The fifth option is the correct answer: mv; 2 mv

3 0

4 years ago

The strength of the electric field of a charged particle becomes greater as the distance from the particle increases. T F

natali 33 [55]

The answer is T it is true

7 0

3 years ago

How far will 20 N of force stretch a spring with a spring constant of 140 N/m?

densk [106]

Answer:

0.143 m

Explanation:

The relationship between force applied on a string and stretching of the spring is given by Hooke's law:

$F=kx$

where

F is the force exerted on the spring

k is the spring constant of the spring

x is the stretching of the spring from its equilibrium position

In this problem, we have:

F = 20 N is the force applied on the spring

k = 140 N/m is the spring constant

Solving for x, we find how far the spring will stretch:

$x=\frac{F}{k}=\frac{20}{140}=0.143 m$

7 0

3 years ago