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Katyanochek1 [597]

3 years ago

11

How do you determine the minimum horizontal velocity

1 answer:

yaroslaw [1]3 years ago

6 0

Divide displacement by time

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Rooms are fitted with ventilators to let the air move around. The phenomenon involved is:

Snezhnost [94]

Answer:

B. Convection

Explanation:

Convection is the process in which heat is transferred from one point to another by the actual movement of the material particles from a region of high temperature to a region of low temperature.

6 0

3 years ago

Read 2 more answers

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

<u>x-component: </u>

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

<u>y-component: </u>

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9 m/s^{2$

$b=2.267 m/s$

$c=0.44 m$

Substituting the known values:

$t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.609 s$ (7)

Substituting (7) in (1):

$x=(3.10 m/s)cos(47\°)(0.609 s)$ (8)

We finally find the horizontal distance traveled by the venom:

$x=1.289 m$

7 0

3 years ago

A car traveling with constant speed travels 150 km in 7200s what is the speed of the car

Oksana_A [137]

Velocity is distance/time

so 150/7200=.0208km/s

unless you have to convert it to miles or something else. but use the formula!

5 0

3 years ago

A uniform metal tube of length 5m and mass 9kg is suspended by two vertical wires attached at 50cm and 150cm respectively from t

Elena-2011 [213]

Answer:

force (tension) of 29.4 N (upward) in 100 cm

force (tension) of 58.4 N (upward) in 200 cm

Explanation:

Given:

Length of tube = 5 m (500 cm)

Mass of tube = 9

Suspended vertically from 150 cm and 50 cm.

Computation:

Force = Mass × gravity acceleration.

Force = 9.8 x 9

Force = 88.2 N

So,

Upward forces = Downward forces

D1 = 150 - 50 = 100 cm

D2 = 150 + 50 = 200 cm

And F1 = F2

F1 x D1 = F2 x D2

F1 x 100 = F2 x 200

F = 2F

Total force = Upward forces + Downward forces

3F = 88.2

F = 29.4 and 2F = 58.8 N

force (tension) of 29.4 N (upward) in 100 cm

force (tension) of 58.4 N (upward) in 200 cm

4 0

3 years ago

Which of the following describes the principle of conservation of charge?

grigory [225]

Answer: The statement "The charge cannot be created or destroyed describes the principle of the conservation of charge".

Explanation:

According to the conservation of charge, the charge can neither be created nor destroyed. It can be transferred from one system to another.

In an isolated system, the total electric charge remains constant. The net quantity of electric charge is always conserved in the universe.

Therefore, "the charge cannot be created or destroyed" describes the principle of the conservation of charge.

7 0

3 years ago