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pantera1 [17]
3 years ago
15

Which of the following is true about wedges?

Physics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

wedges are a type of inclined plane.

Explanation:

i just answered :) :) :)

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A Volt/Amp Is Also Known As.?
maxonik [38]

A volt/amp is also know as a volt ampere

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4 years ago
What do we call the certain electrons that are able to sometimes wander<br> away or be shared? *
Natalka [10]

Answer:

compond

Explanation:

5 0
3 years ago
Acceleration occurs whenever an ___________________ force acts on an object.
leonid [27]
Acceleration occurs whenever the forces on an object are unbalanced.

It's the group of forces on the object that's either balanced or unbalanced.
There's no such thing as "an unbalanced force".

8 0
4 years ago
Read 2 more answers
A uniform 1.0-N meter stick is suspended horizontally by vertical strings attached at each end. A 2.0-N weight is suspended from
fgiga [73]

Answer:

3.5 N

Explanation:

Let the 0-cm end be the moment point. We know that for the system to be balanced, the total moment about this point must be 0. Let's calculate the moment at each point, in order from 0 to 100cm

- Tension of the string attached at the 0cm end is 0 as moment arm is 0

- 2 N weight suspended from the 10 cm position: 2*10 = 20 Ncm clockwise

- 2 N weight suspended from the 50 cm position: 2*50 = 100 Ncm clockwise

- 1 N stick weight at its center of mass, which is 50 cm position, since the stick is uniform: 1*50 = 50 Ncm clockwise

- 3 N weight suspended from the 60 cm position: 3*60 = 180 Ncm clockwise

- Tension T (N) of the string attached at the 100-cm end: T*100 = 100T Ncm counter-clockwise.

Total Clockwise moment = 20 + 100 + 50 + 180 = 350Ncm

Total counter-clockwise moment = 100T

For this to balance, 100 T = 350

so T = 350 / 100 = 3.5 N

4 0
3 years ago
A student, starting from rest, slides down a water slide. On the way down, a kinetic frictional force (a nonconservative force)
katen-ka-za [31]

Answer:

Velocity will be equal to 7.31 m/sec

Explanation:

We have given mass of the student m = 61 kg

Height of the water slide h = 12.3 m

Acceleration due to gravity g=9.8m/sec^2

Potential energy is equal to U=mgh=61\times 9.8\times 12.3=7352.94J

Work done due to friction = -5800 J

So energy remained = 7352.94-5800 = 1552.94 J

This energy will be equal to kinetic energy

So \frac{1}{2}mv^2=1552.94

\frac{1}{2}\times 61\times v^2=1552.94

v^2=50.91

v = 7.13 m/sec

7 0
3 years ago
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