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USPshnik [31]
3 years ago
8

When a huge block of rock is pushed up at a normal fault, a ___ mountain is usually formed. A.fault -block B.dome C.folded D.bas

in
Physics
2 answers:
katrin2010 [14]3 years ago
8 0
The answer is A. Block mountain
DerKrebs [107]3 years ago
3 0

Answer: Option 'A' is correct.

Explanation:

When a huge block of rock is pushed up at a normal fault, a fault block mountain is usually formed.

They are formed by the movement blocks large blocks of crustal when forces in the crust of Earth pull it apart.

Some parts are pushed upward whereas other collapse down.

This led to formation of fault block mountain.

Hence, Option 'A' is correct.

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8 0
2 years ago
A honeybee with a mass of 0.150 g lands on one end of a floating 4.75-g popsicle stick, as shown in (Figure 1) . After sitting a
Alekssandra [29.7K]

Answer:

0.0443 m/s

Explanation:

m_1 = Mass of honeybee = 0.15 g

m_2 = Mass of popsicle stick = 4.75 g

v_1 = Velocity of honeybee

v_2 = Velocity of stick = 0.14 cm/s

In this system the linear momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{4.75\times 0.14}{0.15}\\\Rightarrow v_1=4.43\ m/s

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5 0
2 years ago
Basic explanation of the scientific method
igomit [66]
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5 0
2 years ago
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Triss [41]

Answer:

Jim's kinetic energy is 54.67 J.

Explanation:

Given that,

Mass, m = 15 kg

Velocity, V = 2.7 m/s

We need to find the Jim's kinetic energy. We know that when the object is in motion, it has kinetic energy. This energy is given by :

E=\dfrac{1}{2}mv^2

E=\dfrac{1}{2}\times 15\ kg\times (2.7\ m/s)^2

E = 54.67 J

So, Jim's kinetic energy is 54.67 J. Hence, this is the required solution.

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2 years ago
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