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USPshnik [31]
3 years ago
8

When a huge block of rock is pushed up at a normal fault, a ___ mountain is usually formed. A.fault -block B.dome C.folded D.bas

in
Physics
2 answers:
katrin2010 [14]3 years ago
8 0
The answer is A. Block mountain
DerKrebs [107]3 years ago
3 0

Answer: Option 'A' is correct.

Explanation:

When a huge block of rock is pushed up at a normal fault, a fault block mountain is usually formed.

They are formed by the movement blocks large blocks of crustal when forces in the crust of Earth pull it apart.

Some parts are pushed upward whereas other collapse down.

This led to formation of fault block mountain.

Hence, Option 'A' is correct.

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Convertir 1200 ms a cs<br> Convertir 0,3 mm a cm.
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Answer:

You can do the reverse unit conversion from cm/s to m/s, or enter any two units below: Metre per second (U.S. spelling: meter per second) is an SI derived unit of both speed (scalar) and velocity (vector quantity which specifies both magnitude and a specific direction), defined by distance in metres divided by time in seconds.

Explanation:

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Atoms that are bonded together to form a new material with new<br> properties and characteristics. .
mihalych1998 [28]

Answer:

Explanation:

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3 years ago
Two 800 cm^3 containers hold identical amounts of a monatomic gas at 20°C. Container A is rigid. Container B has a 100 cm^2 pis
Vikki [24]

Answer:

1) Final Temperature of the gas in A will be GREATER than the temperature in B

2) Diagram of both processes on a single PV has been uploaded below

3) The Initial  pressures in containers A and B is 3039.87 J/liters

4) the final volume of container B is 923.36 cm³

Explanation:

Given that;

Temperature = 20°C = 293 K

mass of piston = 10 kg

Area = 100cm³

Volume V = 800 cm³ = 0.8 L

ideal gas constant R = 8.3 J/K·mol

1)

Final Temperature of the gas in A will b GREATER than the temperature in B

2)

Diagram of both processes on a single PV has been uploaded below,

3)

Initial  pressures in containers A and B

PV = nRT

P = RT/V

we substitute

P = (8.3 × 293) /  0.8

P = 2431.9 / 0.8

P = 3039.87 J/liters

Therefore, The Initial  pressures in containers A and B is 3039.87 J/liters

4)

Given that;

power = 25 W

time t = 15s

the final volume of container B = ?

we know that;

work done = power × time

work done = 25 × 15 = 375

Also work done = P( V₂ - V₁ )

so we substitute

375 = 3039.87 ( V₂ - 0.8 )

( V₂ - 0.8 ) = 375 / 3039.87

V₂ - 0.8 = 0.12336

V₂ = 0.12336 + 0.8

V₂ = 0.92336 Litres

V₂ = 923.36 cm³

Therefore, the final volume of container B is 923.36 cm³

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Question 8
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Answer:

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Answer:

Corvette Corvette

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