All categories

2 years ago

What is the range of y = sin θ ?

1 answer:

5 0

The range of a function is the set of all the possible function outputs. We know that sin theta varies between -1 and 1 if we draw a graph. According to the graph, the largest number that is an output of g is -1, and the smallest number is 1. Every number between them is also an output of g for some input. Therefore, the range of g is [-1,1].

You might be interested in

PLEASE HELP 7TH GRADE 100 PTS!!!

MariettaO [177]

f(x) = 5x is linear. Just a straight line with a slope of +5. So if the intervals are both a difference of 1, then the average rate of change will be the same.

f(x2) - f(x1) over x2 - x1. That's the formula for average rate of change.

So for Section A:

f(x) = 5x, (0,1)

[f(1) - f(0)]/(1-0)

= [5(1) - 5(0)]/1

=(5)/1

Do the same for section B and you'll get 5 as well.

I hope this helps you because I have no clue if my answer is right

6 0

3 years ago

Store A is sells 12 juice bottles for $4 and store B sells 18 juice bottles for $6

andrew11 [14]

What's the question!???????

3 0

2 years ago

A sphere of radius r is cut by a plane h units above the equator, where

Anika [276]

Consider the top half of a sphere centered at the origin with radius $r$ , which can be described by the equation

$z=\sqrt{r^2-x^2-y^2}$

and consider a plane

$z=h$

with $0$ . Call the region between the two surfaces $R$ . The volume of $R$ is given by the triple integral

$\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates will help make this computation easier. Set

$\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

Now, the volume can be computed with the integral

$\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta$

You should get

$\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)$

5 0

2 years ago

Use this area model to find<br> 1/4 divided by 3 =

love history [14]

Answer:

Step-by-step explanation:

1/4/3=1/4*1/3=1/12

4 0

3 years ago

Read 2 more answers

Suppose the sales tax rate is 5% on a $1300 tv how much is is the amount of tax?

shepuryov [24]

Answer:

Therefore, amount of tax is $65.

Step-by-step explanation:

Amount of tax = Tax% of $1300

Amount of tax = 5% of $1300

= (5/100) of $1300

= (1/20) of $1300

= $130/2

= $65

3 0

2 years ago