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2 years ago

Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.

Physics

1 answer:

LiRa [457]2 years ago

7 0

Answer:

Time - taken = 2.5 s

deceleration= -8 m/s²

Solution:

Given:

speed, v = 8 m/s

distance, d = 20m

To Find:

deacceleration = ?

As we know speed is defined as

v = d/t

plugging in the values

t = 20/ 8

t = 2.5s

Now from deceleration formula

a = - v/ t

a = - 20/ 2.5

a = - 8 m/s²

Thus, the time taken and acceleration is 2.5 s and -8 m/s²

respectively.

Learn more about deceleration here:

brainly.com/question/13354629

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Mars2501 [29]

There is no need for tangential acceleration when moving in a circle at a constant speed.

<h3>What is centripetal acceleration?</h3>

centripetal acceleration refers to the speed at which a body moves through a circle. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude, the speed, and a direction), when a body travels in a circle, its direction is constantly changing, which causes a change in velocity, which results in an acceleration.

<h3>Which is an example of centripetal acceleration?</h3>

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1 year ago

I have a voltage source of 12V but a light that only burns at 5V. The lamp works on 18 mA. Calculate the resistance that you EXT

ratelena [41]

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop, IR = E- V

IR = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

IR = V

$R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms$

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

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3 years ago

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barxatty [35]

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The moon is always circling around the earth, in a stable orbit. This movement is the reason we see the different phases of the

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Semmy [17]

Answer:

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1 year ago