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bixtya [17]
2 years ago
14

Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.

Physics
1 answer:
LiRa [457]2 years ago
7 0

Answer:

         Time - taken = 2.5 s

          deceleration= -8 m/s²

Solution:

            Given:

                     speed, v = 8 m/s

                 distance, d = 20m

                     

              To Find:

                     deacceleration = ?

               

               As we know speed is defined as

                          v = d/t

                plugging in the values

                          t =  20/ 8

                          t = 2.5s

                Now from deceleration formula

                        a =  - v/ t

                        a = - 20/ 2.5

                        a = - 8 m/s²

          Thus, the time taken and acceleration is 2.5 s and -8 m/s²

          respectively.

          Learn more about deceleration here:

                brainly.com/question/13354629

                       #SPJ4  

               

                       

             

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Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

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8 0
3 years ago
A sound from a source has an intensity of 270 db when it is 1 m from the source. what is the intensity of the sound when it is 3
Lina20 [59]
Sound intensity is inversely proportional to the square of the distance between the source and the receiver.
That is 
I = k/r^2
 where
 k = constant
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When r=1,  the intensity is I₁ = k/1 = k
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