Suppose a car traveling at 8m/s is brought to rest in a distance of 20m.what is it's deceleration and time taken.

Physics

1 answer:

LiRa [457]2 years ago

7 0

Answer:

Time - taken = 2.5 s

deceleration= -8 m/s²

Solution:

Given:

speed, v = 8 m/s

distance, d = 20m

To Find:

deacceleration = ?

As we know speed is defined as

v = d/t

plugging in the values

t = 20/ 8

t = 2.5s

Now from deceleration formula

a = - v/ t

a = - 20/ 2.5

a = - 8 m/s²

Thus, the time taken and acceleration is 2.5 s and -8 m/s²

respectively.

Learn more about deceleration here:

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