The pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
Therefore, option A is correct option.
Given,
Mass m = 14g
Volume= 3.5L
Temperature T= 75+273 = 348 K
Molar mass of CO = 28g/mol
Universal gas constant R= 0.082057L
Number of moles in 14 g of CO is
n= mass/ molar mass
= 14/28
= 0.5 mol
As we know that
PV= nRT
P × 3.5 = 0.5 × 0.082057 × 348
P × 3.5 = 14.277
P = 14.277/3.5
P = 4.0794 atm
P = 4.1 atm.
Thus we concluded that the pressure will 14. 0 g of co exert in a 3. 5 l container at 75°c is 4.1atm.
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Given Information:
Number of turns = N = 1130 turns
Length of solenoid = L = 0.430 m
Magnetic field = B = 1.0x10⁻⁴ T
Required Information:
Current = I = ?
Answer:
I = 0.0302 A
Explanation:
The current flowing in the solenoid winding can be found using
I = BL/μ₀N
Where μ₀ is the permeability of free space, N is the number of turns, B is the magnetic field and L is the length of solenoid
I = 1.0x10⁻⁴*0.430/4πx10⁻⁷
*1130
I = 0.0302 A
or
I = 30.28 mA
Answer:
The plane would need to travel at least 
(
.)
The 
runway should be sufficient.
Explanation:
Convert unit of the the take-off velocity of this plane to 
:
.
Initial velocity of the plane: 
.
Take-off velocity of the plane 
.
Let 
denote the distance that the plane travelled along the runway. Since acceleration is constant but unknown, make use of the SUVAT equation 
.
Notice that this equation does not require the value of acceleration. Rather, this equation make use of the fact that the distance travelled (under constant acceleration) is equal to duration 
times average velocity 
.
The distance that the plane need to cover would be:
.
It can be found in granitic and basaltic rock.
The resistance expected of the heater is 50.1 ohms.
<h3>What is resistance?</h3>
Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).
To calculate the resistance of the heater, we use the formula below.
<h3>Formula:</h3>
- R = V²/P............. Equation 1
Where:
- R = Resistance of the heater
- P = Power of the heater
- V = Voltage supplied to the heater
From the question,
Given:
- V = 480 V
- P = 4.6 kW = 4600 W
Substitute these values into equation 1
- R = (480²)/4600
- R = 50.1 ohms.
Hence, the resistance expected of the heater is 50.1 ohms.
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