The pressure on a volume of liquid V = 1.0 mº at the surface is approximately equal to the atmospheric pressure Patm = 1.00 x 10
1 answer:
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Answer:
0.02 m
Explanation:
R₁ = initial distance jumped by jumper = 7.4 m
R₂ = final distance jumped by jumper = ?
θ₁ = initial angle of jump = 45°
θ₂ = final angle of jump = 42.9°
= speed at which jumper jumps at all time
initial distance jumped is given as
final distance jumped is given as
Dividing final distance by initial distance
distance lost is given as
d =
d = 7.4 - 7.38
d = 0.02 m