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barxatty [35]
4 years ago
9

A reader's

Physics
1 answer:
LiRa [457]4 years ago
5 0

Answer:

activity level

Explanation:

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A ruby laser delivers a 16.0-ns pulse of 4.20-MW average power. If the photons have a wavelength of 694.3 nm, how many are conta
stepan [7]

Answer:

The  value is  n  =  2.347 *10^{17} \  photons

Explanation:

From the question we are told that

     The  amount of power delivered is  P  =  4.20 \  M W  =  4.20  *10^{6} \  W

      The  time taken is  t =  16.0ns  =  16.0 *10^{-9} \  s

       The  wavelength is  \lambda  =  694.3 \  nm =  694.3 *10^{-9} \  m

     

Generally the energy delivered is  mathematically represented as

     E  =  P  * t  =  \frac{n  *  h  *  c  }{\lambda }

Where  h is the Planck's constant with value  h  =  6.262  *10^{-34} \  J \cdot  s

           c  is the speed of light with value  c =  3.0*10^{8} \  m/s

     

So  

    4.20 *10^{6}  *  16*10^{-9}=  \frac{n  *  6.626 *10^{-34}  *  3.0*10^{8}  }{694.3 *10^{-9}}

=>    n  =  2.347 *10^{17} \  photons

4 0
3 years ago
Please help me !!!!!
riadik2000 [5.3K]
C. 70 inches is the answer
6 0
3 years ago
Starting from rest, a rocket accelerates at 20 m/s². How far will it travel in the first 4
guajiro [1.7K]

Answer:

80m

Explanation:

using

S=ut+1/2at².

u=0

t=4s

v=20 m/s².

s=0Xt+1/2x10x4².

S=5x16

=80m

3 0
3 years ago
Which of these parts of a telescope is used to make the light focused from distant stars visible to the human eye?
Zina [86]
The correct option is A.
A telescope is an optical instrument that is used to observe celestial bodies in order to gather information about them. There are different types of telescopes but all of them have some common parts. One of the common parts is the eye piece. The eye piece is the part of the telescope that one looks through and is the part that makes the focused light visible to the eye. The eye piece is made up of magnifying lenses.<span />
4 0
3 years ago
An unfingered guitar string is 0.68 m long and is tuned to play E above middle C (330 Hz).
dem82 [27]

Answer:

Length (L2) = 0.51m

Wavelength of string (∆) = 1.02m

Wavelength of sound produced = 0.7795m

Explanation:

Using the equation L1F1 = L2F2

L1 = 0.68m, F1 = 330Hz, F2 = 440Hz

Therefore, (0.68m)(330Hz) = (L2)(440Hz)

L2 = 0.68m × 330hz/440hz

L2 = 0.51m

0.68m - 0.51m = 0.17m from the but

B. ∆ = 2×length (L2)

∆ = 2(0.51) = 1.02m

C. Frequency (f) = 440Hz

V = ∆f

343m/s =∆×440hz

∆ = 343m/s/440hz

∆ = 0.7795m

3 0
3 years ago
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