The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.
<u>Explanation:</u>
<u>Given</u>
t=?
d=6m
v=3*10^8 m/s
we have, v=d/t
here t=d/v
t=6m/3*10^8 m/s
v=2*10^-8 m/s
The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.
<u></u>
PE = 0.5 × k × x²
PE potential Energy
k spring constant
x stretch/compression of the spring
Conservation of momentum: total momentum before = total momentum after
Momentum = mass x velocity
So before the collision:
4kg x 8m/s = 32
1kg x 0m/s = 0
32+0=32
Therefore after the collision
4kg x 4.8m/s = 19.2
1kg x βm/s = β
19.2 + β = 32
Therefore β = 12.8 m/s
Answer:
maximum height on moon is 6 times more than the maximum height on Earth
Explanation:
Let the Astronaut has its maximum speed by which he can jump is "v"
now for the maximum height that it can jump is given as

now from above equation we will have

now we have

now if Astronaut jump on the surface of moon with same speed
then we know that the acceleration of gravity on surface of moon is 1/6 times the gravity on earth
so at surface of moon we have

now we have

so maximum height on moon is 6 times more than the maximum height on Earth
Answer:
the magnitude of the magnetic force on the wire is 0.2298 N
Explanation:
Given the data in the question;
we know that, the magnitude of magnetic force is given as;
|F
| = I(
×
)
given that
I = 2.6 A
= 0.17
= 0.52
so we substitute
|F
| = 2.6( 0.17i" × 0.52j" )
|F
| = 0.2298 N
Therefore, the magnitude of the magnetic force on the wire is 0.2298 N