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inn [45]
3 years ago
12

How much NaNO3 will dissolve into 100 g of Water at 35*C? * 45 g 100 g 80 g 150 g

Chemistry
1 answer:
VARVARA [1.3K]3 years ago
8 0

Answer:

100g

Explanation:

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Why are the alkali metals and the halogens very reactive
jeyben [28]

Answer:

Answer in explanation

Explanation:

The reactivity or passiveness of an element depends solely on how close it is to attain a noble gas configuration. This means the closer an element is to attain a noble gas configuration, the greater its reactivity in both direction, positively or negatively.

Alkali metals belong to group 1 of the periodic table while halogens belong to group 17 of the periodic table. This means they are just one electron away from achieving the stability of a noble gas configuration. While alkali metals need to lose one electron to form a univalent positive ion, halogens news to gain one electron to form a univalent negative ion.

They tend to go about this vigorously and as such undergo several chemical reactions because of that single electron they neeed.

4 0
3 years ago
Using your own words define a scientific law
OleMash [197]
A scientific law is a statement that is universally accepted and answers the "how?" question.

Hope this helps!
4 0
3 years ago
WILL GIVE YOU BRAINLIEST!!!
Papessa [141]

Answer:

A ability to decompose

B reactivity

Explanation:

Chemical properties are those properties that tell us about what a substance can do as regards to whether or not the substance reacts with other substances.

Examples are flammability, rusting of iron, precipitation, decomposition of water by an electric current.

The ability to decompose and reactivity are chemical properties of a substance.

  • Physical properties tells us everything about what a substance is when no change is occurring to its constituents.
  • Examples are state of matter, color, odor, taste, texture, hardness e.t.c

5 0
3 years ago
Read 2 more answers
Properties of carbon responsible for the pressence of millions of organic compound ​
Minchanka [31]

Answer:

Carbon has the ability to form very long chains of interconnecting C-C bonds. This property allows carbon to form the backbone of organic compounds, carbon-containing compounds, which are the basis of all known organic life. Nearly 10 million carbon-containing organic compounds are known.

5 0
3 years ago
Aluminum reacts with sulfur gas to produce aluminum sulfide. a) What is the limiting reactant? What is the excess reagent? b) Ho
Sophie [7]

Answer:

a) Limiting: sulfur. Excess: aluminium.

b) 1.56g Al₂S₃.

c) 0.72g Al

Explanation:

Hello,

In this case, the initial mass of both aluminium and sulfur are missing, therefore, one could assume they are 1.00 g for each one. Thus, by considering the undergoing chemical reaction turns out:

2Al(s)+3S_2(g)\rightarrow 2Al_2S_3(s)\\

a) Thus, considering the assumed mass (which could be changed based on the one you are given), the limiting reagent is identified as shown below:

n_S^{available}=1.00gS_2*\frac{1molS_2}{64gS_2} =0.0156molS_2\\n_S^{consumed\ by \ Al}=1.00gAl*\frac{1molAl}{27gAl}*\frac{3molS_2}{2molAl}=0.0556molS_2

Thereby, since there 1.00g of aluminium will consume 0.0554 mol of sulfur but there are just 0.0156 mol available, the limiting reagent is sulfur and the excess reagent is aluminium.

b) By stoichiometry, the produced grams of aluminium sulfide are:

m_{Al_2S_3}=0.0156molS_2*\frac{2molAl_2S_3}{3molS_2} *\frac{150gAl_2S_3}{1molAl_2S_3} =1.56gAl_2S_3

c) The leftover is computed as follows:

m_{Al}^{excess}=(0.0556-0.0156)molS_2*\frac{2molAl}{3molS_2}*\frac{27gAl}{1molAl} =0.72 gAl\\

NOTE: Remember I assumed the quantities, they could change based on those you are given, so the results might be different, but the procedure is quite the same.

Best regards.

7 0
3 years ago
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