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stiv31 [10]
3 years ago
14

Si una persona sana que no tiene mutaciones en el cromosoma 4 decide tener hijos con una persona heterocigota (A/a) que padece d

e la enfermedad de huntington, ¿cuál es la probabilidad de que esta pareja tenga hijos que padescan la enfermedad?
Biology
1 answer:
inessss [21]3 years ago
3 0

Answer and Explanation:

<u>Cruza</u>: persona sana sin mutaciones con persona portadora

El parental sano aporta alelos normales del gen a la descendencia

El parental portador aporta un alelo normal y un alelo alterado. Tiene el 50% de probabilidad de transmitir la enfermedad a la progenie.

Parental)    AA   x   Aa

Gametas) A    A    A   a

Cuadro de Punnet)   A       A

                           A   AA    AA

                           a    Aa    Aa

F1) 2/4 = 1/2 = 50% de la progenie seran individuos sanos AA

    2/4 = 1/2 = 50% de la progenie seran individuos portadores Aa

Como uno de los progenitores es portador, cada individuo tiene un 50% de posibilidades heredar el gen alterado.

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