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Mashcka [7]
2 years ago
15

The motion of a car on a position-time graph is represented with a horizontal line. What does this indicate about the car's moti

on?
A.It's not moving.
B. It's moving at a constant speed.
C. It's moving at a constant velocity.
D. It's speeding up.
Physics
2 answers:
Ksenya-84 [330]2 years ago
5 0

Answer: The answer is B

Explanation: It is staying in a steady speed position

kumpel [21]2 years ago
5 0

Answer:B it is going a constant speed

                                                       

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I need help with my science.
Ostrovityanka [42]

Answer:

1: 2

2: 5

Explanation:

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8 0
2 years ago
If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to
Vaselesa [24]

Answer:

g_2=6.8125 m^2/sec

Explanation:

We know that

Acceleration due to gravity g is given by the formula

g= \frac{GM}{r^2}

G= gravitational constant

M= mass of the Earth

r= radius of the earth

g_1 = GM/r_1^2

Let acc. due to gravity after radius is 20% greater be g_2

then

g_2=GM/r_2^2

=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125

5 0
2 years ago
Read 2 more answers
As the ball rolls down the ramp, there are changes in kinetic and potential energy. How much kinetic energy does the ball have w
Trava [24]

Answer: C. 50j

Explanation:

5 0
3 years ago
Read 2 more answers
The hydrogen molecule will start to vibrate at temperatures above roughly 1000 K. At this high temperature, what is the ratio of
Elena L [17]

Answer:

Explanation:

At the temperature of 1000K , hydrogen will have following degree of freedom

translational = 3

rotational = 2

vibrational = 1

Total = 6

Internal energy = 6N  x 1 /2 k T where N is no of molecules

E₁ = 3 N kT

At the temperature of 1000K , helium  will have following degree of freedom

translational = 3

rotational = 0

vibrational =  0

Total = 3

Internal energy = 3N  x 1 /2 k T where N is no of molecules

E₂ = 3 / 2 N kT

Ratio =  E₁ / E₂

=  2

6 0
3 years ago
A thin, uniform metal bar, 2.00 m long and weighing 90.0 N, is hanging vertically from the ceiling by a frictionless pivot. Sudd
matrenka [14]

Answer:

(a) The "angular speed" is 5.88 rad/s.

Explanation:

Given values,

The length of the bar is L = 2m

The weight of the bar is w = 90 N

The metal bar is hanging vertically from the ceiling by a frictionless pivot  

The mass of the ball is m = 3kg

The distance between the ceiling and the ball is d = 1.5m

\text { The "initial speed of the ball" is } V_{i}=10 \mathrm{m} / \mathrm{s}

\text { The "final speed of the ball" is } V_{f}=6 \mathrm{m} / \mathrm{s}

(a) Calculating the angular speed:    

W_{\mathrm{f}}=\left(3 \mathrm{mg} \mathrm{d} \frac{V_{i}+V_{f}}{w l^{2}}\right)

W_{f}=\left(3 \times 3 \times 9.8 \times 1.5 \times \frac{10+6}{90 \times 2^{2}}\right)

W_{f}=\frac{2116.8}{360}

\mathrm{W}_{\mathrm{f}}=5.88 \mathrm{rad} / \mathrm{s}

The angular speed is 5.88 rad/s.

(b) The "angular momentum" is conserved because the torque is not exerted by "the pivot" on the system about the "axis of rotation" but the "linear momentum" is not conserved because "the pivot" exerts a "vertical" and a "horizontal force" on the system during the collision.

8 0
3 years ago
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