When air is blown into the open pipe,
L =
where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation
⇒λ=
Note here that n=1 is for fundamental, n=2 is first harmonic and so on..
⇒ third harmonic will be n=4
Given L=6m, n=4, solving for λ we get:
λ= =3m
Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:
c=f.λ Or f=
⇒f=
≈115 Hz
The final vertical velocity of the object is 705.6 m
Explanation:
Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of
towards the ground due to gravity.
Therefore, we can use the following suvat equation:
where
v is the final vertical velocity
u is the initial vertical velocity
is the acceleration
t is the time
Since the object is dropped,
u = 0
Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:
Learn more about free fall:
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