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irina1246 [14]
3 years ago
13

Write newtone first law

Physics
2 answers:
nika2105 [10]3 years ago
6 0

an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

gtnhenbr [62]3 years ago
4 0

Newtons first law is that an Object that is in motion will stay in motion until an unbalanced force acts upon it, and part 2 is that an object at rest will stay at rest until and unbalanced force acts upon it

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Suppose you are helping a friend move. The friend asks you stand in the back of a pickup truck to hold a piano because there is
Maslowich

<u><em>Explanation:</em></u>

This exposes the individual to danger. <em>Remember</em>, the Newton Law of motion which says that an object under the state of rest will remain in that state (inertia) unless when acted upon by an external force.

In this scenario, standing at the back of the pickup truck presents danger especially if the truck suddenly stops; this individual would experience an upward thrust due to inertia that may disbalance him.

5 0
3 years ago
Suppose a miracle car has a 100% efficient engine and burns fuel having an energy content of 40 MJ/L. If the air resistance and
Stolb23 [73]

Answer:

Distance traveled in 1 liter = 40 km

Explanation:

Distance traveled = Energy / Opposing force = 40 x 10^6 J / 1000 N = 40000 m or 40 km

So, the car will moves to a distance of 40 km per liter under the opposing force of 1000 N…

3 0
3 years ago
Two velcro-covered pucks slide across the ice, collide and stick to one another. Their interaction with the ice is frictionless.
balu736 [363]

Answer:

<em>1. False</em>

<em>2. True</em>

<em>3. False</em>

<em>4. True</em>

Explanation:

<u>Conservation of Momentum</u>

According to the law of conservation of linear momentum, the total momentum of the system formed by both pucks won't change regardless of their interaction if no external forces are acting on the system.

The momentum of an object of mass ma moving at speed va is

p_a=m_a.v_a

The total momentum of both pucks at the initial condition is

p_1=m_a.v_a+m_b.v_b

Both pucks are moving to the right and puck B has twice the mass of puck A (let's call it m), thus

m_a=m

m_b=2m

We are given

v_a=6\ m/s\\v_b=2\ m/s

The total initial momentum is

p_1=6m+2(2m)=10m

At the final condition, both pucks stick together, thus the total mass is 3m and the final speed is common, thus

p_2=3m.v'

Equating the initial and final momentum

10m=3m.v'

Solving for v'

v'=10/3\ m/s=3.33\ m/s

1. Compute the initial kinetic energy:

\displaystyle K_1=\frac{1}{2}mv_a^2+\frac{1}{2}2mv_b^2

\displaystyle K_1=\frac{1}{2}m\cdot 6^2+\frac{1}{2}2m\cdot 2^2

K_1=18m+4m=22m

The final kinetic energy is

\displaystyle K_2=\frac{1}{2}mv'^2+\frac{1}{2}2mv'^2

\displaystyle K_2=\frac{1}{2}m\cdot 3.33^2+\frac{1}{2}2m\cdot 3.33^2

K_2=16.63m

As seen, part of the kinetic energy is lost in the collision, thus the statement is False

2. The initial speed of puck B was 2 m/s and the final speed was 3.33 m/s, thus it increased the speed: True

3. The initial speed of puck A was 6 m/s and the final speed was 3.33 m/s, thus it decreased the speed: False

4. The momentum is conserved since that was the initial assumption to make all the calculations. True

p_1=10m

p_2=3m.v'=3m(10/3)=10m

Proven

5 0
3 years ago
A leopard of mass 65kg climbs 7m up a tall tree. Calculate how much gravitational potential energy it gains. Assume g=10N/kg.
vesna_86 [32]

Answer: 4550 Joules

The formula for potential energy in gravitational field is as follows:

E_{pot} = mgh=65kg \cdot 10 \frac{N}{kg} \cdot 7m = 4550 J

8 0
3 years ago
WILL GIVE BRAINLY!!!
Gnoma [55]
The answer is apogee my dude
7 0
4 years ago
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