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Stolb23 [73]
3 years ago
7

If three balls of different materials were dropped at the same time from the same height, which would hit the ground first? (Ass

ume there is no
air resistance.)
Physics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

It depends of the mass and weight of each of the materials

Explanation:

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A tennis ball, a bowling ball, and a feather are dropped from the top of a tall building at the same time. Consider what you hav
lord [1]
The object that reaches the ground first is thebowling ball i think because it weighs heavier but when the tennis ball hits the ground it will bounce again and again till it stops and the bowling ball will just stop it wont bounce
7 0
3 years ago
Shorter the vibrating part more will be the pitch. How?​
Lina20 [59]

Answer:When the length of a string is changed, it will vibrate with a different frequency.Shorter strings have higher frequency and therefore higher pitch.

6 0
3 years ago
In the image, the net force is _______.
Sveta_85 [38]

Your correct answer would be 0 N

The forces are pulling in opposite directions, therefore they cancel each other out.

Hope that helps!!

:)

4 0
4 years ago
Calculate the electric charge of the glass ball
-Dominant- [34]

Answer:

As per Coulomb's law we know that force between two charges is given as

F = \frac{kq_1q_2}{r^2}F=

r

2

kq

1

q

2

here we know that

q_1 = 2.5 \times 10^{-6} Cq

1

=2.5×10

−6

C

q_2 = -5.0 \times 10^{-6} Cq

2

=−5.0×10

−6

C

r = 0.0050 mr=0.0050m

now from above formula we will have

F = \frac{(9 \times 10^9)(2.5 \times 10^{-6})(5 \times 10^{-6})}{(0.0050)^2}F=

(0.0050)

2

(9×10

9

)(2.5×10

−6

)(5×10

−6

)

F = 4500 NF=4500N

so they will attract towards each other as they are opposite in nature with force F = 4500 N

4 0
3 years ago
A bowling ball weighing 71.2 N is attached to the ceiling by a 3.30 m rope. The ball is pulled to one side and released; it then
wolverine [178]

Answer:

a. The acceleration of the bowling ball is 9.5 m/s² toward the center

b.  The tension in the rope is 140.24 N

Explanation:

given information:

ball weight,  W = 71.2 N

the length of rope, R = 3.30 m

ball speed, v = 5.60 m/s

a. The acceleration of the bowling ball, α

α = \frac{v^{2} }{R}

where

α = the acceleration

v = the speed

R = radius

thus

α = \frac{v^{2} }{R}

  = \frac{5.60^{2} }{3.3}

  = 9.5 m/s² toward the center

b. The tension in the rope?

according to the Newton's second law

ΣF = m a

where

F = force

m = mass

a = acceleration

so,

ΣF = m a

T - W = m a

T = m a + W

  = (W a/g) + W

  = (71.2 x 9.5/9.8) + 71.2

  = 140.24 N

4 0
3 years ago
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