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Zepler [3.9K]
3 years ago
12

How much heat is required to increase the temperature of 35.0 grams of water from 10.0°C to 45.0°C? (The specific heat of water

is 4.18 J/g°C)
Chemistry
2 answers:
MariettaO [177]3 years ago
8 0
The correct answer is 5,120
kati45 [8]3 years ago
7 0
Q = mCΔT
Q is heat in Joules, m is mass, C is the specific heat of water, delta T is the change in temperature

Q = (35g)(4.18)(35 degrees) = 5121 Joules or 5.12 kJ required


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The equation presented above may not be balanced yet. Then, we determine the number of mmols of C, H, and O in the product using the given masses.
    
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(2) 1.92 mg H2O
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