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bonufazy [111]
2 years ago
11

Can someone pls explain this question to me. Thanks in advance! ​

Physics
1 answer:
KonstantinChe [14]2 years ago
4 0

Answer: 7.407 m/s^{2}

Explanation:

In this question we are asked to find the cheeta's accelaration and we assume it is constant. Therefore, we can use the folowing equation:

V=V_{o}+at (1)

Where:

V=80 \frac{km}{h} \frac{1000 m}{1 km} \frac{1 h}{3600 s}=22.22 m/s is the cheeta's final speed

V_{o}= 0 m/s is the cheeta's initial speed

t=3 s is the time in which the cheeta passes from V_{o} to V

a is the cheeta's acceleration

Isolating a from (1):

a=\frac{V}{t} (2)

a=\frac{22.22 m/s}{3 s} (3)

Finally:

a+7.407 m/s^{2}

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The pressure exerted by the concrete cylinder is 2.60 pound/in².

We need to know about the pressure to solve this problem. Pressure is a unit that describes how much force is applied to a surface area. It can be determined as

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From the question above, we know that

F = 375 pound

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1 year ago
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Nimfa-mama [501]

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The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

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2. Now when the cooler air meets the warm gas present in the coils, it

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Amount of pressure of liquid increases with ?​
Pachacha [2.7K]

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3 0
2 years ago
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Diamonds are usually found in pipes 50 to 200 m across made of ________.
Leokris [45]
I believe the correct answer would be kimberlite. Diamonds are usually found in pipes 50 to 200 m across made of kimberlite. It is an igneous rock that is known to contain traces of diamonds. It is named base on the town where it was discovered which is Kimberley, South Africa. 



7 0
3 years ago
A 1.0-kg block of aluminum is at a temperature of 50°C. How much thermal energy will it lose when its temperature is reduced by
Marat540 [252]

Answer:

22425 J

Explanation:

From the question,

Applying

Q = cm(t₂-t₁).................. Equation 1

Where Q = Thermal Energy, c = specific heat capacity of aluminium, m = mass of aluminium, t₂ = Final Temperature, t₁ = Initial Temperature.

Given: c = 897 J/kg.K, m = 1.0 kg, t₁ = 50 °C, t₂ = 25 °C (The final temperature is reduced by half)

Substitute these values into equation 1

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Q = -22425 J

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5 0
2 years ago
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