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marysya [2.9K]
3 years ago
9

Calculate the enthalpy change for the thermite reaction: 2al(s)+fe2o3(s)→2fe(s)+al2o3(s), δh∘rxn=−850 kj when 4.00 mol of al und

ergoes the reaction with a stoichiometrically equivalent amount of fe2o3.
Chemistry
1 answer:
kolezko [41]3 years ago
6 0

<u>Given:</u>

Enthalpy change ΔH for the thermite reaction = -850 kJ

Moles of Al involved = 4

<u>To determine:</u>

Reaction enthalpy when 4 moles of Al reacts

<u>Explanation:</u>

The thermite reaction is-

2Al(s) + Fe2O3(s) → 2Fe(s) + Al2O3(s)

When 2 moles of Al react the enthalpy change is -850 kJ

therefore, when 4 moles of Al reacts, the change in enthalpy is-

= 4 moles * (-850) kJ/2 moles = -1700 kJ

Ans: Enthalpy change is -1700 kJ


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