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AleksandrR [38]
3 years ago
7

A particular energy level in the hydrogen atom has E = -2.42 x 10-19 J. Use Bohr's model of the energy levels in hydrogen to cal

culate n for this level. Recall that atomic number (Z) of hydrogen is 1.
Chemistry
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

n=3

Explanation:

The expression for the energy of an electron for the hydrogen atom in the nth orbit is:-

E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules

Given that:-

E_n=-2.42\times 10^{-19}\ Joules

Applying in the equation to find the value of n as:-

-2.42\times 10^{-19}=-2.18\times 10^{-18}\times \frac{1}{n^2}

n^2=\frac{2.18\times 10^{-18}}{2.42\times 10^{-19}}

n=\sqrt{\frac{21.8}{2.42}}=3

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A+gas+at+250k+and+15atm+has+a+molar+volume+12%+less+than+the+perfect+gas+law+character. +calculate+the+compressibility+factor
shutvik [7]

The compression factor based on the information given is 0.083.

<h3>How to calculate the compression factor?</h3>

The way to calculate the compression factor goes this:

V(ideal) = RT/P

= (0.0821 × 250)/15

= 1.368

V(real) will be:

= V(ideal)/12

= 1.368/12 = 0.114

The compression factor will be:

= 1.368/(12 × 1.368)

= 0.083

Therefore, the compression factor is 0.083.

Learn more about compression factor on:

brainly.com/question/24261456

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6 0
2 years ago
A sample of aluminum is placed in a 25 ml graduated cylinder containing 10 mL of water. The level of water rises to 18 mL. Alumi
anastassius [24]

To determine the mass of the sample, first find the volume difference after and before the aluminum was placed, the volume change is equal to the volume of the submerged object, in this case aluminum.

Then knowing volume of aluminum and the density of it, we can solve for the mass.

D = m/v

Dv = m

2.7 g/ml • 8 ml = 21.6 grams.

4 0
3 years ago
Read 2 more answers
If I have a 50 liter container that holds 45 moles of gas at a temperature of 200 0C, what is the pressure inside the container?
Bezzdna [24]

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8 0
3 years ago
A volume measured by a graduated cylinder that was marked in 100 mL
Natali [406]

The volume measured using such a cylinder will be reported to the nearest 10th mL.

<h3>Cylinder graduation</h3>

10 mL graduated cylinders are always read to the nearest two decimal places.

100 mL graduated cylinders are always read to the nearest 1 decimal place. The nearest 1 decimal place is the same thing as the nearest 10th.

Thus, a reading made using a 100mL increment graduated cylinder would be reported to the nearest 10th mL.

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8 0
1 year ago
In a single replacement reaction between 2.57 moles Aluminum and 3.59 moles of Hydrochloric acid, how many moles of Hydrogen can
Alenkasestr [34]

Answer:

1.795 mole of H2.

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

2Al + 6HCl —> 2AlCl3 + 3H2

Step 2:

Determination of the limiting reactant.

From the balanced equation above,

2 moles of Al reacted with 6 moles

Therefore, 2.57 moles of Al will react with = (2.57 x 6)/2 = 7.71 moles of HCl.

From the calculation made above, it will require a higher amount of HCl than what was given to react completely with 2.57 moles of Al. Therefore, HCl is the limiting reactant and Al is the excess reactant.

Step 3:

Determination of the number of mole H2 produced from the reaction.

Here, we shall be using the limiting reactant because it will produce the maximum yield of the reaction since all of it were consumed by the reaction.

The limiting reactant is HCl and the amount of H2 produce can be obtained as follow:

From the balanced equation above,

6 moles of HCl reacted to produce 3 moles of H2.

Therefore, 3.59 moles of HCl will produce = (3.59 x 3)/6 = 1.795 mole of H2.

From the calculations made above, 1.795 mole of H2 is produced from the reaction.

5 0
3 years ago
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