2 years ago

PLEASE HELP ASAP!!!! I need to know some machines that put force where you want it

Physics

1 answer:

andriy [413]2 years ago

6 0

Answer:

A wheel and axle, force multipliers and a lever.

Explanation:

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What is the acceleration during the pushing-off phase, in m/27 Express your answer in meters per second squared. A bush baby, an

Sindrei [870]

Answer:

$a = 12.78 g's$

Explanation:

Height reached by the object after push off is given as

$H = 2.3 m$

$v_f^2 - v_i^2 = 2 a s$

now we have

$0 - v^2 = 2(-9.81)(2.3)$

$v = 6.72 m/s$

now we know that this push last for total distance of 0.18 m

so during the push we will have

$v_f^2 - v_i^2 = 2 a d$

$6.72^2 - 0 = 2a(0.18)$

$a = 125.35 m/s^2$

now in terms of g = 9.81 m/s/s we have

$a = \frac{125.35}{9.81} gs$

$a = 12.78 g's$

6 0

2 years ago

Coherent light with wavelength 610 nm passes through two very narrow slits, and theinterference pattern is observed on a screen

andriy [413]

Answer:

= 1220 nm

= 1.22 μm

Explanation:

given data:

wavelength $\lambda = 610 nm = 610\times 10 ^{-9} m$

distance of screen from slits D = 3 m

1st order bright fringe is 4.84 mm

condition for 1 st bright is

$d sin \theta =\lambda$ ---( 1)

and $tan \theta = \frac{y}{ D}$

$\theta = tan^{-1}\frac{(y }{D})$

= 0.0924 degrees

plug theta value in equation 1 we get

$d sin ( 0.0924) = 610 \times 10 ^{-9}$

$d = 3.78\times 10^{-4} m$

condition for 1 st dark fringe

$d sin \theta =\frac{λ'}{2}$

$\lambda '= 2 d sin\theta$

= 2λ since from eq (1)

= 1220 nm

= 1.22 μm

7 0

3 years ago

rosijanka [135]

Answer:

its deepend on where you stand but. most cases g = 10 m/s²

W = M X G

W = 13 kg x 10 m/s²

W = 130 N

Explanation:

option b is correct brainlist ke

3 0

2 years ago

23. Milo created the data table based on his science experiment. What was the velocity of the

Tems11 [23]

6 m/s because the position of the object was increasing 6 m every second

8 0

2 years ago

Becky has a shower and uses 20,000g of water with a specific heat capacity of 4200J/KG. When the water is supplied with 336,000J

lara [203]

Answer:

46°C

Explanation:

q = mCΔT

336,000 J = (20 kg) (4200 J/kg/°C) (50°C − T)

T = 46°C

7 0

3 years ago