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Studentka2010 [4]
3 years ago
11

Whenever a net force acts on an object, there is a change in the objects ____

Physics
1 answer:
maw [93]3 years ago
4 0

Velocity. Net force causes acceleration and acceleration causes a change in direction and/or magnitude of velocity

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Desiree has a scientific question that she wants to investigate. She has developed a hypothesis and method for her experiment. W
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The next scientific step is to collect data to test her Hypothesis. 
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3 years ago
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Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets
PolarNik [594]

 Step by step solution :

standard deviation is given by :

\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}

where, \sigma is standard deviation

\bar{x} is mean of given data

n is number of observations

From the above data, \bar{x}=24.88

Now, if x=24.8, then (x-\bar{x})^2=0.0064

If  x=23.9, then (x-\bar{x})^2=0.9604

if x=26.1, then (x-\bar{x})^2=1.4884

If x=25.1, then (x-\bar{x})^2=0.0484

If x=24.5, then (x-\bar{x})^2=0.1444

so, \sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}

\sum (x-\bar{x})^2 =2.648

\sqrt{\sum \frac{(x-\bar{x})^2}{n}}

\sigma =0.7277

No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.

6 0
3 years ago
A helium-filled balloon occupies a volume of 15 cubic meters at sea level. the balloon is released and raises to a point in the
Elena L [17]

According to Boyle’s law, For a fixed amount of an ideal gas kept at a fixed temperature, P (pressure) and V (volume) are inversely proportional.

Therefore,

P_{1} V_{1} =P_{2} V_{2}

Given P_{1} = 1 atm , V_{1} = 15 \ cubic \ meter and P_{2} = 0.75\ atm.

Thus,

V_{2} = \frac{P_{1}\times V_{1}  }{ P_{2} } = \frac{1\times 15}{0.75} =20 m^3

5 0
3 years ago
A circular horizontal surface having an area of 1020.5 mm2that is completely immersed in a fluid experiences a uniform force of
Bingel [31]

Answer:

Faya vei Abhikesh brass hahahahahaha

Explanation:

3 0
3 years ago
A ball is thrown vertically upwards from the edge of the cliff and hits the ground at the base of the cliff with a speed of 30 m
olya-2409 [2.1K]

To solve this problem we will apply the linear motion kinematic equations. From the definition of the final velocity, as the sum between the initial velocity and the product between the acceleration (gravity) by time, we will find the final velocity. From the second law of kinematics, we will find the vertical position traveled.

v = v_0 -gt

Here,

v = Final velocity

v_0 = Initial velocity

g = Acceleration due to gravity

t = Time

At t = 4s, v = -30m/s (Downward)

Therefore the initial velocity will be

-30 = v_0 -9.8(4)

v_0 = 9.2m/s

Now the position can be calculated as,

y = h +v_0t -\frac{1}{2}gt^2

When it has the ground, y=0 and the time is t=4s,

0 = h+(9.2)(4)-\frac{1}{2} (9.8)(4)^2

h = 41.6m

Therefore the cliff was initially to 41.6m from the ground

7 0
3 years ago
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