They both flow in currents. Water has a pump that works like a battery and pipes that work like a circuit.
Answer:
speed=abs(v)=40ms^-1
Explanation:
acceleration, a = (v-u)/t
since initial velocity u=0 (at rest) and a=8ms^-2,
8=v/5
hence after 5 seconds, v=40ms^-1
The shadow that will be protected on the ground will represent the hawk's horizontal position. therefore it will move at the hawk's horizontal velocity component, which is:
5*cos(60) = 2.5 m/s
Answer:
a). 6 seconds
b). 12 seconds
c). 176.4 meters
Explanation:
a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,
v = u - gt
where v = final velocity
u = initial velocity = 58.8 m per sec
g = gravitational pull = 9.8 m per sec²
t = duration of the flight
At the peak height,
v = 0
Therefore, 0 = 58.8 - (9.8)(t)
t = 
= 6 seconds
b). Total time of flight = 2(Time taken to go up)
= 2×6
= 12 sec
c). Formula to get the peak height is,

h = (58.8)6 - 
= 352.8 - 176.4
= 176.4 meters