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3 years ago

6

A pendulum has 844 J of potential energy at the highest point of its swing. How much kinetic energy will it have at the bottom o

f its swing?

1 answer:

Stolb23 [73]3 years ago

8 0

844J.
Assuming that there were no encumbrances during it's foreswing and it reached it's full potential at apogee.

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Please help on this one?

koban [17]

Using the given equation:

di = 20.0 * 10.0 / 20.0 - 10.0

di = 200/10

di = 20.0 cm

The answer is A.

6 0

3 years ago

Read 2 more answers

Equal masses of he and ne are placed in a sealed container. What is the partial pressure of he if the total pressure in the cont

EastWind [94]

Answer:

6 atm.

Explanation:

Let the mass of both be m

Then moles of He = m/ 4

Moles of Ne = m/ 20

mole fraction of He = Moles of He/ Total moles = m/4/ (m/4 + m/20) = 0.25 m/0.3m = 0.83

Pressure of He = Mole fraction×total pressure = 0.83 × 6 atm = 5 atm

6 0

2 years ago

Consider the following waves representing electromagnetic radiation: An illustration shows two waves representing electromagneti

Murljashka [212]

Answer:

a) red wave hs a longer wavelength than the green wave

b)f = 1.875 10¹¹ Hz , f_green = 5.45 10¹⁴Hz

c) E = 1.24 10⁻²² J , E_green = 3.6 10⁻¹⁹ J

d) The red wave is in the infrared range, heat waves

The green wave is in the visible wavelength

Explanation:

a) The green wave are on the left in the electromagnetic spectrum so the red wave has a longer wavelength than the green wave

The green wavelength is in the range of 550 10⁻⁹ m

The speed of the wave is

c = λ f

f = c /λ

b) The frequency of the red wave is

f = 3 10⁸ / 1.6 10⁻³

f = 1.875 10¹¹ Hz

For the green wave

f_green = 3 10⁸/550 10⁻⁹

f_green = 5.45 10¹⁴Hz

c) The photon energy is given by the Planck equation

E = h f

E = 6.63 10⁻³⁴ 1.875 10¹¹

E = 1.24 10⁻²² J

For the green wave

E_green = 6.63 10⁻³⁴ 5.45 10¹⁴

E_green = 3.6 10⁻¹⁹ J

d) The speed of electromagnetic waves is constant and has a value of 3 108 m / s

e)

The red wave is in the infrared range, heat waves

The green wave is in the visible wavelength

6 0

3 years ago

What is the definition of visible white light wave (RoyGBive)

uranmaximum [27]

There's no such thing as a wave of white light. Every light wave with
a certain wavelength has some color. White light is a mixture of all
the different wavelengths with all of the different visible colors.
They're ALL there in white light. When they all enter your eye at
the same time, your brain gets the message of brightness with
no particular color, which we call "white light".

5 0

2 years ago

Suppose 3 mol of neon (an ideal monatomic gas) at STP are compressed slowly and isothermally to 0.19 the original volume. The ga

Radda [10]

Answer:

a. 273 K b. 90.1 K c. 5.26 atm d. 0.33 atm

Explanation:

For isothermal expansion PV = constant

So, P₁V₁ = P₂V₂ where P₁ = initial pressure of gas = 1 atm (standard pressure), V₁ = initial volume of gas, P₂ = final pressure of gas and V₂ = final volume of gas,

So, P₁V₁ = P₂V₂

P₂ = P₁V₁/V₂

Since V₂/V₁ = 0.19,

P₂ = P₁V₁/V₂

P₂ = 1 atm (1/0.19)

P₂ = 5.26 atm

For an adiabatic expansion, PVⁿ = constant where n = ratio of molar heat capacities = 5/3 for monoatomic gas

So, P₂V₂ⁿ = P₃V₃ⁿ where P₂ = initial pressure of gas = 5.26 atm, V₂ = initial volume of gas, P₃ = final pressure of gas and V₃ = final volume of gas,

So, P₂V₂ⁿ = P₃V₃ⁿ

P₃ = P₂V₂ⁿ/V₃ⁿ

P₃ = P₂(V₂/V₃)ⁿ

Since V₃ = V₁ ,V₂/V₃ = V₂/V₁ = 0.19

1/0.19,

P₃ = P₂(V₂/V₃)ⁿ

P₃ = 5.26 atm (0.19)⁽⁵/³⁾

P₃ = 5.26 atm × 0.0628

P₃ = 0.33 atm

Using the ideal gas equation

P₃V₃/T₃ = P₄V₄/T₄ where P₃ = pressure after adiabatic expansion = 0.33 atm , V₃ = volume after adiabatic expansion, T₃ = temperature after adiabatic expansion P₄ = initial pressure of gas = P₁ = 1 atm , V₄ = initial volume of gas = V₁ and T₄ = initial temperature of gas = T₁ = 273 K (standard temperature)

P₃V₃/T₃ = P₄V₄/T₄

T₃ = P₃V₃T₄/P₄V₄

T₃ = (P₃/P₄)(V₃/V₄)T₂

Since V₃ = V₄ = V₁ and P₄ = P₁

V₃/V₄ = 1 and P₃/P₄ = P₃/P₁

T₃ = (P₃/P₁)(V₃/V₄)T₂

T₃ = (0.33 atm/1 atm)(1)273 K

T₃ = 90.1 K

So,

a. The highest temperature attained by the gas is T₁ = 273 K

b. The lowest temperature attained by the gas = T₃ = 90.1 K

c. The highest pressure attained by the gas is P₂ = 5.26 atm

d. The lowest pressure attained by the gas is P₃ = 0.33 atm

6 0

3 years ago