The time when the particle is at rest is at 1.63 s or 3.36 s.
The velocity is positive at when the time of motion is at 
.
The total distance traveled in the first 10 seconds is 847 m.
<h3>When is a particle at rest?</h3>
- A particle is at rest when the initial velocity of the particle is zero.
The time when the particle is at rest is calculated as follows;
s(t) = 2t³ - 15t² + 33t + 17
The velocity is positive at when the time of motion is as follows;
.
The total distance traveled in the first 10 seconds is calculated as follows;
Learn more about motion of particles here: brainly.com/question/11066673
Answer:
The temperature of the steam during the heat rejection process is 42.5°C
Explanation:
Given the data in the question;
the maximum temperature T
in the cycle is twice the minimum absolute temperature T
in the cycle
T = 0.5T
now, we find the efficiency of the Carnot cycle engine
η
= 1 - T/T
η = 1 - T/0.5T
η = 0.5
the efficiency of the Carnot heat engine can be expressed as;
η = 1 - W
/Q
where W is net work done, Q is is the heat supplied
we substitute
0.5 = 60 / Q
Q = 60 / 0.5
Q = 120 kJ
Now, we apply the first law of thermodynamics to the system
W = Q - Q
60 = 120 - Q
Q = 60 kJ
now, the amount of heat rejection per kg of steam is;
q = Q/m
we substitute
q = 60/0.025
q = 2400 kJ/kg
which means for 1 kilogram of conversion of saturated vapor to saturated liquid , it takes 2400 kJ/kg of heat ( enthalpy of vaporization)
q = h
= 2400 kJ/kg
now, at h = 2400 kJ/kg from saturated water tables;
T = 40 + ( 45 - 40 ) ( 
)
T = 40 + (5) × (0.5)
T = 40 + 2.5
T = 42.5°C
Therefore, The temperature of the steam during the heat rejection process is 42.5°C
To solve this exercise it is necessary to apply the concepts related to Centripetal and Perimeter acceleration of a circle.
The perimeter of a circle is defined by
Where,
r= radius
While centripetal acceleration is defined by
Where,
v= velocity
r= radius
PART A)
The distance of a body can be defined based on the speed and the time traveled, that is
x = v*t
For our values the distance is equal to
x = 15*115=1725m
The plane when going to make the turn from east to south makes a quarter of the circumference that is
The same route you take is the distance traveled, that is
PART B)
With the radius is possible calculate he centripetal acceleration,
Therefore the radius of the curva that the plane follows in making the turn is 1098.17m with a centripetal acceleration of 
Answer:
a. V=11.84 m/s
b.x=0.052m
Explanation:
a).
Given
,
, 
.
b).
No friction on the ball so:
option B open system
because in open system energy and mass can escape from the system or can be added to it.
