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Elenna [48]
3 years ago
10

10.Give an example of an adaptation in birds, where shape of beak is related to the eating habits of that bird.

Chemistry
1 answer:
iVinArrow [24]3 years ago
4 0

Answer:

It isn't only for the eating habits but also for building nests, hunting small insects, birds, other creatures including defence. Birds have a narrow small throat so the beak helps ripping off small peices of a big animal l(small bird) and for insects they crush and swallow it, they se their beak for feeding their children by grinding food in their beak and transferring it to the youngsters mouth

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What occurs when energy is removed from a liquid-vapor system in equilibrium
yulyashka [42]

<span>The answer is that the number of water molecules  increases and that of vapor decreases.  When energy is removed from the system it would do so mostly as heat. Therefore the energy in the system would decrease and the molecules would vibrate at lower energies. Therefore, several water vapor molecules would turn back to water.  </span>






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14. As the moles of salt added are increased, what<br> happens to the melting point of the water?
Vika [28.1K]
Salt lowers the freezing/melting point of water, so in both cases the idea is to take advantage of the lower melting point. Ice forms when the temperature of water reaches 32 degrees Fahrenheit (0 degrees Celsius).
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bulgar [2K]
Using AVOs number 
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4 0
4 years ago
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Calculate the pH after 10 mL of 1.0 M sodium hydroxide is added to 60 mL of 0.5M acetic acid.
baherus [9]

Explanation:

It is given that the total volume is (10 mL + 60 mL) = 70 mL.

Also, it is known that M_{1}V_{1} = M_{2}V_{2}

Where,    V_{1} = total volume

               V_{2} = initial volume

Therefore, new concentration of CH_{3}COOH = \frac{M_{2}V_{2}}{V_{1}}

                                        = \frac{60 \times 0.5}{70}

                                        = 0.43 M

New concentration of NaOH = \frac{M_{2}V_{2}}{V_{1}}

                                               = \frac{10 \times 1.0}{70}

                                               = 0.14 M

So, the given reaction will be as follows.

              CH_{3}COOH + OH^{-} \rightarrow CH_{3}COO^{-} + H_{2}O

Initial:             0.43          0.14                     0

Change:          -0.14        -0.14                    0.14

Equilibrium:    0.29          0                       0.14

As it is known that value of pK_{a} = 4.74

Therefore, according to Henderson-Hasselbalch equation calculate the pH as follows.

           pH = pK_{a} + log \frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}

                 = 4.74 + log \frac{0.14}{0.29}

                 = 4.74 + (-0.316)

                 = 4.42

Therefore, we can conclude that the pH of given reaction is 4.42.

6 0
3 years ago
Which polyatomic ion has a charge of 3-?
skad [1K]
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3 years ago
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