Answer:
p = 8N/mm2
Explanation:
given data ;
diameter of cylinder = 150 mm
thickness of cylinder = 6 mm
maximum shear stress = 25 MPa
we know that
hoop stress is given as =
axial stress is given as =
maximum shear stress = (hoop stress - axial stress)/2
putting both stress value to get required pressure
t = 6 mm
d = 150 mm
therefore we have pressure
p = 8N/mm2
Answer:
Explanation:
Given
mass of bus along with travelers travelling in North direction is
speed of bus towards North
mass of bus travelling in South direction is
speed of bus
mass of each Passenger in south moving bus
Momentum of North moving bus
Momentum with south moving bus
For total momentum to be towards south
should be greater than 0
thus for least value of n
From the given information in the question, the correct option is Option 1: 14 cm.
A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:
PE = k
Where PE is the energy, k is the spring constant and x is extension.
i. Given that: PE = 10 J and x = 10 cm, then;
PE = k
10 = k
20 = 100k
k = 0.2 J/cm
ii. To determine how far the spring is needed to be stretched, given that PE = 20 J.
PE = k
20 = (0.2)
40 = 0.2
= 200
x =
= 14.1421
x = 14.14 cm
So that;
x is approximately 14.00 cm.
Thus, the spring need to be stretched to 14.00 cm to give the spring 20 J of elastic potential energy.
For more information, check at: brainly.com/question/1352053.