Scientists use this part of the electromagnetic spectrum to diagnose broken bones.

Physics

2 answers:

lesantik [10]3 years ago

7 0

They use x-rays to diagnose broken bones

Volgvan3 years ago

6 0

Answer:

X-Rays

Explanation:

X-Rays are most widely used to diagnose broken bones without making an incision in the body. X Rays are part of the EM spectrum having a wave length in the range of 0.01 to 10 nanometers. They have a property of traversing through thick objects without being much absorbed or scattered, thus making it very useful for such procedure.

You might be interested in

Which is a FALSE statement about elements? Select one: a. Each element has its own neutron number. b. Each element has its own a

Nata [24]

It is A. Number of neutrons can differ with and be the same any given element.

3 0

3 years ago

Which sentence correctly uses a comma to separate coordinate adjectives?

lubasha [3.4K]

Answer:

Explanation:

Coordinate adjectives are adjectives that describe the same noun equally. They should be separated with commas. In this sentence, both red and round are describing the ball. The correct answer is, "The red, round ball is Adley's favorite toy to play with."

6 0

2 years ago

If you know the answer please answer the following question down in the picture below.

Harlamova29_29 [7]

I think it’s the second one: magnetic domains must come in pairs—one north and one south

3 0

3 years ago

How to find a planet’s gravitational field strength using its radius?

grin007 [14]

The gravitational field strength is approximately equal to 10 N.

<u>Explanation:</u>

Gravitational field strength is the measure of gravitational force acting on any object placed on the surface of the planet. Generally, the mass of the object is considered as 1 kg.

So the gravitational field strength will be equal to the gravitational force acting on the object.

The formula for gravitational field strength is

$g = \frac{F}{m}$

Here g is the gravitational field strength, m is the mass of the object placed on the surface and F is the gravitational force acting on the object.

Since, the mass of any object placed on the surface of earth will be negligible compared to the mass of Earth, so the mass of the object is considered as 1 kg.

Then the g = F

And $F =\frac{GMm}{r^{2} }$

Here G is the gravitational constant, M is the mass of Earth and m is the mass of the object placed on the surface, while r is the radius of the Earth.

$g = F = \frac{6 \times 10^{24} \times 6.67 \times 10^{-11} \times 1}{(6.6 \times 10^{6}) ^{2} }$