Work = force × distance
= 35 N × 200 m
= 7000 J
Answer:
Speed of the speeder will be 28 m/sec
Explanation:
In first case police car is traveling with a speed of 90 km/hr
We can change 90 km/hr in m/sec
So 
Car is traveling for 1 sec with a constant speed so distance traveled in 1 sec = 25×1 = 25 m
After that car is accelerating with
for 7 sec
So distance traveled by car in these 7 sec

So total distance traveled by police car = 224 m
This distance is also same for speeder
Now let speeder is moving with constant velocity v
so 
v = 28 m/sec
Answer:
v ≈ 7900 m/s
Explanation:
centripetal force will equal gravity force
mv²/R = mg
v²/R = g
v² = Rg
v = √(Rg)
v = √(6.4e6(9.8))
v = 7.91959...e+3
v ≈ 7900 m/s
of course, at those velocities and that deep into the atmosphere, the satellite would quickly burn up, slow down, and cause tremendous damage to buildings etc. with the sonic boom shock wave. It would also have to avoid a lot of mountains as 4000 m is not that high.
Answer:
The pressure at point 2 is 
Explanation:
From the question we are told that
The speed at point 1 is 
The gauge pressure at point 1 is 
The density of water is 
Let the height at point 1 be
then the height at point two will be

Let the diameter at point 1 be
then the diameter at point two will be

Now the continuity equation is mathematically represented as

Here
are the area at point 1 and 2
Now given that the are is directly proportional to the square of the diameter [i.e
]
which can represent as

=> 
where c is a constant
so 
=> 
=> 
Now from the continuity equation
=>
=>

Generally the Bernoulli equation is mathematically represented as

So
=> 
substituting values


Answer:
Magnitude = 3.64 ×
စ = 43.9°
Explanation:
given data
ship to travel = 1.7 ×
kilometers
turn = 70°
travel an additional = 2.7 ×
kilometers
solution
we will consider here
Px = 1.7 ×
Py = 0
Qx =2.7 ×
cos(70)
Qy= 2.7 ×
sin(70)
so that
Hx = Px + Qx ............1
Hx = 2.62 ×
and
Hy = Py + Qy ..........2
Hy = 2.53 ×
so Magnitude = 
Magnitude = 3.64 ×
so direction will be
tan စ = Hy ÷ Hx ......................3
tan စ =
tan စ = 0.9656
စ = 43.9°