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3 years ago

WILL NAME BRAINLIEST !!

Physics

2 answers:

Dmitry_Shevchenko [17]3 years ago

7 0

the answer is a unbalanced force is acting on the brick

viva [34]3 years ago

7 0

Answer:

B). An unbalanced force is acting on the brick.

Explanation:

Here as we can see the given figure there are two forces acting on the block

1. $F_1 = 7,205 N$ Upwards

2. $F_2 = 7,210 N$ Downwards

so here as we can see that force downwards is more in magnitude while upward force is less.

So here since downward force is more so the box will accelerate downwards and net force is given as

$F_{net} = F_2 - F_1$

$F_{net} = 7210 - 7205 = 5 N$

so here net force on this box is 5 N downwards and since there is unbalanced force on the box so box can not remains at rest.

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A marathon runner completes a 42.188–km course in 2 h, 36 min, and 12 s. there is an uncertainty of 23 m in the distance travele

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The percentage uncertainty in the distance is 0.054%.

Uncertainty in a measurement measures the deviation of the measured values from the true value.

The distance d can be expressed in the form d+/-Δd, where Δd is the absolute uncertainty in the measurement of distance.

The percentage uncertainty is given by,

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The uncertainty in the measurement of distance is 23 m. Express the uncertainty in km.

$\Delta d =\frac{23 m}{1000 m/km} =0.023 km$

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2 years ago

At what temperature is Fahrenheit scale reading equal to twice of celsius?

gayaneshka [121]

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2 years ago

A juggler throws a bowling pin straight up in the air. After the pin leaves his hand and while it is in the air, which statement

WINSTONCH [101]

Answer:

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(d) option is correct.

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3 years ago

A hockey puck on a frozen pond is given an initial speed of 20.0 m/s. If the puck always remains on the ice and slides 115 m bef

bekas [8.4K]

Answer:

μ_k = 0.1773

Explanation:

We are given;

Initial velocity;u = 20 m/s

Final velocity;v = 0 m/s (since it comes to rest)

Distance before coming to rest;s = 115 m

Let's find the acceleration using Newton's second law of motion;

v² = u² + 2as

Making a the subject, we have;

a = (v² - u²)/2s

Plugging relevant values;

a = (0² - 20²)/(2 × 115)

a = -400/230

a = -1.739 m/s²

From the question, the only force acting on the puck in the x direction is the force of friction. Since friction always opposes motion, we see that:

F_k = −ma - - - (1)

We also know that F_k is defined by;

F_k = μ_k•N

Where;

μ_k is coefficient of kinetic friction

N is normal force which is (mg)

Since gravity acts in the negative direction, the normal force will be positive.

Thus;

F_k = μ_k•mg - - - (2)

where g is acceleration due to gravity.

Thus,equating equation 1 and 2,we have;

−ma = μ_k•mg

m will cancel out to give;

-a = μ_k•g

μ_k = -a/g

g has a constant value of 9.81 m/s², so;

μ_k = - (-1.739/9.81)

μ_k = 0.1773

3 0

3 years ago