Answer:
1.51 x 10²⁴ things
Explanation:
According to Avogadro's Constant.
1 mole of any substance, constains 6.02×10²³ particles of that subtance.
From the question,
If we have 2.50 moles of anything,
1 mole of anything ⇒ 6.02×10²³ things
2.50 moles of anything ⇒ y things
solving for y
y = (2.50× 6.02×10²³)/1
y = 15.05×10²³
y = 1.505×10²⁴
y ≈ 1.51×10²⁴
Answer:
1600
Explanation:
5×10^4÷2.5×10^2
(5×10^4)
(10^4)
(5×40)
(200)
(200÷2.5)
(80)
(80×10^2)
(10^2)
(20)
(80×20)
Answer is 1600.
Sorry if it's not correct.
Answer:
1. Orbital diagram
2p⁴ ║ ↑↓ ║ "↑" ║ ↑
2s² ║ ↑↓ ║
1s² ║ ↑↓ ║
2. Quantum numbers
- <em>n </em>= 2,
- <em>l</em> = 1,
- = 0,
- = +1/2
Explanation:
The fill in rule is:
- Follow shell number: from the inner most shell to the outer most shell, our case from shell 1 to 2
- Follow the The Aufbau principle, 1s<2s<2p<3s<3p<4s<3d<4p<5s<4d<5p<6s<4f<5d<6p<7s<5f<6d<7p
- Hunds' rule: Every orbital in a sublevel is singly occupied before any orbital is doubly occupied. All of the electrons in singly occupied orbitals have the same spin (to maximize total spin).
So, the orbital diagram of given element is as below and the sixth electron is marked between " "
2p⁴ ║ ↑↓ ║ "↑" ║ ↑
2s² ║ ↑↓ ║
1s² ║ ↑↓ ║
The quantum number of an electron consists of four number:
- <em>n </em>(shell number, - 1, 2, 3...)
- <em>l</em> (subshell number or orbital number, 0 - orbital <em>s</em>, 1 - orbital <em>p</em>, 2 - orbital <em>d...</em>)
- (orbital energy, or "which box the electron is in"). For example, orbital <em>p </em>(<em>l</em> = 1) has 3 "boxes", it was number from -1, 0, 1. Orbital <em>d</em> (<em>l </em>= 2) has 5 "boxes", numbered -2, -1, 0, 1, 2
- (spin of electron), either -1/2 or +1/2
In our case, the electron marked with " " has quantum number
- <em>n </em>= 2, shell number 2,
- <em>l</em> = 1, subshell or orbital <em>p,</em>
- = 0, 2nd "box" in the range -1, 0, 1
- = +1/2, single electron always has +1/2
Gold/Atomic mass
196.96657 u ± 0.000004 u
Potassium/Atomic mass
39.0983 u ± 0.0001 u
Francium/Atomic number
87
Copper/Atomic mass
63.546 u ± 0.003 u
Bromine/Atomic mass
79.904 u ± 0.001 u
Arsenic/Atomic number
33
I would imagine that n-butanol would have the higher boiling point because it has less branching and therefore stronger intermolecular forces between molecules.