The total power delivered by the battery if the lightbulbs are connected is 9V^2/R
<h3>Power of a battery</h3>
The formula for calculating the power of a battery is expressed according to the equation;
Power = v^2/RT
where
R is the total resistance
v is the voltage or emf
If there are 3 identical lightbulbs, each having constant resistance R, then;
1/RT = 1/R + 1/R + 1/R
1/RT = 3/R
RT = R/3
The voltage drop across each lightbulbs will be the same for parallel connection, hence;
Power = 3V^2/(R/3)
Power = 9V^2/R
Hence the total power delivered by the battery if the lightbulbs are connected is 9V^2/R
Learn more on power here: brainly.com/question/24858512
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Answer: 4.7m/s²
Explanation:
According to newton's first law,
Force = mass × acceleration
Since we are given more the one force, we will take the resultant of the two vectors.
Mass = 2.0kg
F1+F2 = (3i-8j)+(5i+3j)
Adding component wise, we have;
F1+F2 = 3i+5i-8j+3j
F1+F2 = 8i-5j
Resultant of the sum of the forces will be;
R² = (8i)²+(-5j)²
Since i.i = j.j = 1
R² = 8²+5²
R² = 64+25
R² = 89
R = √89
R = 9.4N
Our resultant force = 9.4N
Substituting in the formula
F = ma
9.4 = 2a
a = 9.4/2
a = 4.7m/s²
Therefore, magnitude of the acceleration of the particle is 4.7m/s²
No they say "Watch out it's the fuzz"
