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Svetlanka [38]
3 years ago
14

X=(150^2•sin(2•42))/9.8

Physics
2 answers:
qwelly [4]3 years ago
8 0

Answer:

2283.341086

Explanation: Just plug the equation into the calculator as is

amid [387]3 years ago
3 0

Answer:

2283.3410863

Explanation:

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If you we're in charge of designing a wire to cart electricity across your city, state or provide, which of the following proper
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It should be fibre optic cable , buried underground

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An incident on route 12 summary?I need to describe what happens in the book in a short summary can anyone help?
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Explanation: I HOPE THAT HELPED

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3 years ago
The greater the amplitude of a wave a. The quieter the sound b. The higher the frequency of the sound c. The dimmer the light in
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The owner of a hobby store bought a case of 9-volt batteries for $61.00. He marked the price up such that his profit was $3.75 p
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3 years ago
Some hypothetical alloy is composed of 12.5 wt% of metal A and 87.5 wt% of metal B. If the densities of metals A and B are 4.27
densk [106]

Answer:

The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

Explanation:

Given that,

Weight of metal A = 12.5%

Weight of metal B = 87.5%

Length of unit cell = 0.395 nm

Density of A = 4.27 g/cm³

Density of B= 6.35 g/cm³

Weight of A = 61.4 g/mol

Weight of B = 125.7 g/mol

We need to calculate the density of the alloy

Using formula of density

\rho=n\times\dfrac{m}{V_{c}\times N_{A}}

n=\dfrac{\rho\timesV_{c}\times N}{m}....(I)

Where, n = number of atoms per unit cells

m = Mass of the alloy

V=Volume of the unit cell

N = Avogadro number

We calculate the density of alloy

\rho=\dfrac{1}{\dfrac{12.5}{4.27}+\dfrac{87.5}{6.35}}\times100

\rho=5.98

We calculate the mass of the alloy

m=\dfrac{1}{\dfrac{12.5}{61.4}+\dfrac{87.5}{125.7}}\times100

m=111.15

Put the value into the equation (I)

n=\dfrac{5.9855\times(0.395\times10^{-9}\times10^{2})^3\times6.023\times10^{23}}{111.15}

n=1.99\approx 2\ atoms/cell

Hence, The number of atoms in the unit cell is 2, the crystal structure for the alloy is body centered cubic.

5 0
3 years ago
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