The integrated rate law expression for a first order reaction is
where
[A0]=100
[At]=6.25
[6.25% of 100 = 6.25]
k = 9.60X10⁻³s⁻¹
Putting values
taking log of 100/6.25
100/6.25 = 16
ln(16) = 2.7726
Time = 2.7726 / 0.0096 = 288.81 seconds
A lab worker receives an average radiation
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Answer : The pressure it exert under these new conditions will be, 87 atm
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 19 atm
= final pressure of gas = ?
= initial volume of gas = 100 L
= final volume of gas = 20 L
= initial temperature of gas =
= final temperature of gas =
Now put all the given values in the above equation, we get:
Therefore, the pressure it exert under these new conditions will be, 87 atm