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vova2212 [387]
2 years ago
11

In general, what is used to separate mixtures?

Chemistry
1 answer:
Bas_tet [7]2 years ago
4 0
I would say (Separating funnel)
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Which is regarding enzyme inhbition
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Explanation:

An enzyme inhibitor is a molecule that binds to an enzyme and decreases its activity. ... Since blocking an enzyme's activity can kill a pathogen or correct a metabolic imbalance, many drugs are enzyme inhibitors. They are also used in pesticides.

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What is the average deer per month
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Answer:

25

Explanation:

explain no need it is perfect

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For each of the following sublevels, give the n and l values and the number of orbitals: (a) 5s; (b) 3p; (c) 4f
OverLord2011 [107]

Answer:

(a) 5s. n = 5. Sublevel s, l = 0. Number of orbitals = 1

(b) 3p. n = 3. Sublevel p, l = 1. Number of orbitals = 3

(c) 4f. n =4. Sublevel f, l = 3. Number of orbitals = 7

Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Sublevel number, 0 ≤ l ≤ n − 1

So,

(a) 5s. n = 5, shell number 5. Sublevel s, l = 0. Number of orbitals = 2l +1 = 1

(b) 3p. n = 3, shell number 3. Sublevel p, l = 1. Number of orbitals = 2l +1 = 3

(c) 4f. n =4, shell number 4. Sublevel f, l = 3. Number of orbitals =  2l +1 = 7

6 0
3 years ago
Which of the following options correctly ranks solid iodine, liquid bromine, and chlorine gas in order of increasing intermolecu
tatuchka [14]

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solid iodine chlorine gas

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3 years ago
A critical reaction in the production of energy in biological systems is the hydrolysis of adenosine triphosphate (ATP) to adeno
Archy [21]

Answer:

ΔG° of reaction =  -47.3 x 10^{3} J/mol      

Explanation:

As we can see, we have been a particular reaction and Energy values as well.

ΔG° of reaction = -30.5 kJ/mol

Temperature = 37°C.

And we have to calculat the ΔG° of reaction in the biological cell which contains ATP, ADP and HPO4-2:

The first step is to calculate the equilibrium constant for the reaction:

Equilibrium Constant K = \frac{[HPO4-2] x [ADP]}{ATP}

And we have values given for these quantities in the biological cell:

[HP04-2] = 2.1 x 10^{-3} M

[ATP] = 1.2 x 10^{-2} M

[ADP] = 8.4 x 10^{-3} M

Let's plug in these values in the above equation for equilibrium constant:

K = \frac{[2.1x10^{-3}] x [8.4x10^{-3}] }{[1.2 x 10^{-2}] }

K = 1.47 x 10^{-3} M

Now, we have to calculate the ΔG° of reaction for the biological cell:

But first we have to convert the temperature in Kelvin scale.

Temp = 37°C

Temp = 37 + 273

Temp = 310 K

ΔG° of reaction = (-30.5 10^{3}) + (8.314)x (310K)xln(0.00147)

Where 8.314 = value of Gas Constant

ΔG° of reaction = (-30.5 x 10^{3}) + (-16810.68)

ΔG° of reaction = -47.3 x 10^{3} J/mol

5 0
2 years ago
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