Powdered coke prevent the heat loss. As a result, it prevents burning of carbon electrodes.
Answer: I found this online. Hope it helps you.
Explanation:
This pressure is transmitted throughout the liquid and makes it more difficult for bubbles to form and for boiling to take place. If the pressure is reduced, the liquid requires less energy to change to a gaseous phase, and boiling occurs at a lower temperature.
The correct answer is 2.53 g of precipitate, BaCrO4.
Option (i) would have the highest 2nd Ionization Energy.
Option (i) is Sodium.
Can be Written as 2, 8 , 1
For its 1st Ionization energy... It'd be extremely easy to remove that Electron cos its on the outermost shell.
Now After Removing that Electron...
Sodium's Electronic Configuration Reduces to that of Neon Which is 2, 8.
Neon has a very stable Octet.
It would take an ENORMOUS amount of energy to break its Octet stability... that is... Remove 1 electron from its Octet.
So
Option (i) [Sodium] has the highest 2nd Ionization Energy
The moles of HCl to neutralize the sodium hydroxide produced is<u> 0.0135 mole. </u>
Neutralization or neutralization is a chemical response wherein an acid and a base react quantitatively with each other. In a reaction in water, neutralization outcomes in there being no excess of hydrogen or hydroxide ions gift in the answer.
<u>calculation:-</u>
<u />
2Na + 2H₂O -----> 2NaOH + H₂
2 mol or 46g of Na produces 80 grams of NaOH
∴ 0.31 g of Na will produce = 80/46 × 0.31
= 0.54 gram of NaOH.
mol of NaOH = 0.54/40
= 0.0135
Since both Hcl and NaOH have the same valance factor,
1 mole NaOH is needed to neutralize 1 mol HCl
∴ 0.0135 mole of NaOH will need = 0.0135 mole of HCl
mass = 0.0135 × 36.5
=<u> 0.493 grams of HCL.</u>
Learn more about neutralizing here:-brainly.com/question/23008798
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