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OlgaM077 [116]
3 years ago
7

In the electrolysis of water, 2H2O → 2H2 + O2, if the volume of oxygen produced was 8 mL, what would be the volume of hydrogen p

roduced?
a. 4 mL
b. 8 mL
c. 16 mL
d. 24 mL
Chemistry
1 answer:
NISA [10]3 years ago
8 0

Answer:

16ml

Explanation:

2H2O → 2H2 + O2

2mol      2mol     1mol

volume of oxygen produced =8ml

1mole of a gas contains 22.4dm³

8ml will be equal to 8ml/22.4dm³  number of moles of oxygen gas

Using the stoichoimetric co-efficients;2moles of H2 and 1mol of Oxygen were produced

so number of moles of hydrogen will be [(2*8ml)/22.4dm³moles

but 1mol contains 22.4dm³

[(2*8ml)/22.4dm³moles   will contain x

cross multiply;

x= (2*8ml)mol/22.4dm³ *22.4dm³/1mol

x=16ml

simply put ; using the stochoimetric coefficients if 2moles of H2 correspond to 1mol of O2, thus 16ml of H2 will correspod to 8ml of O2.

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Unlike most chemical changes, most physical changes are easily reversed. When Adrian's teacher dissolves some sugar in a beaker
pochemuha

Answer:

By heating the solution

Explanation:

Physical changes and chemical changes are the two types of changes that a substance undergoes. Physical change does not alter the substance's chemical composition, hence, can be easily reversed. There is also no new product formed. This is contrary to the occurrences of a chemical change, which cannot be reversed after a new product has been formed.

A physical change is what occurs when Adrian's teacher dissolves some sugar in a beaker of water to form a sugar solution. This change does not involve any new product formation, hence, can be reversed. The sugar can be derived back from the solution by HEATING THE SOLUTION. The water (solvent) will evaporate and the sugar (solute) will precipitate.

8 0
2 years ago
list all of the species that would have a net attraction to the positive charge: CH4, CH2Cl2, H3O+, H2O, C2H2Cl2, CO2, N3-,
Rzqust [24]
A species with a positive charge will have a net attraction to a species with a negative charge. Among the choices, N3- is the only one attracted to a positive charge.
4 0
3 years ago
Knowing that all three-sided figures are triangles is an example of:
pogonyaev

Answer:

B. Concept Formation

Explanation:

All the other answer choices are not equivalent.

Hope this helps!

Brainliest??

5 0
3 years ago
Read 2 more answers
Equation is balanced already
mojhsa [17]

Answer:

1.) 13 g C₄H₁₀

2.) 41 g CO₂

Explanation:

To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.

Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)

Molar Mass (C₄H₁₀): 58.124 g/mol

Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)

Molar Mass (CO₂): 44.007 g/mol

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O

 48 g O₂             1 mole             2 moles C₄H₁₀            58.124 g
---------------  x  -----------------  x  -------------------------- x  ------------------  =  
                         31.996 g              13 moles O₂               1 mole

=  13 g C₄H₁₀

 48 g O₂             1 mole               8 moles CO₂            44.007 g
---------------  x  -----------------  x  -------------------------- x  ------------------  =  
                         31.996 g              13 moles O₂               1 mole

=  41 g CO₂

6 0
1 year ago
An ideal gas in a cylindrical container of radius r and height h is kept at constant pressure p. The bottom of the container is
Juli2301 [7.4K]

Answer:

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}  

Explanation:

The gas ideal law is  

PV= nRT (equation 1)

Where:

P = pressure  

R = gas constant  

T = temperature  

n= moles of substance  

V = volume  

Working with equation 1 we can get  

n =\frac{PV}{RT}

The number of moles is mass (m) / molecular weight (mw). Replacing this value in the equation we get.

\frac{m}{mw} =\frac{PV}{RT}  or  

m =\frac{P*V*mw}{R*T}   (equation 2)

The cylindrical container has a constant pressure p  

The volume is the volume of a cylinder this is

V =(pi)*r^{2}*h

Where:

r = radius  

h = height  

(pi) = number pi (3.1415)

This cylinder has a radius, r and height, h so the volume is  V =(pi)*r^{2}*h

Since the temperatures has linear distribution, we can say that the temperature in the cylinder is the average between the temperature in the top and in the bottom of the cylinder. This is:  

T =\frac{T_{1} + T_{O}}{2}  

Replacing these values in the equation 2 we get:

m =\frac{P*V*mw}{R*T}   (equation 2)

m =\frac{p*(pi)*r^{2}*h*mw}{R*\frac{T_{1} + T_{O}}{2}}    

8 0
3 years ago
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