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allochka39001 [22]
3 years ago
12

This is what the enzyme looks like at 4C

Chemistry
1 answer:
Art [367]3 years ago
5 0

Answer:

molecular diagram 3 or 2 is correct answer I hope it helps you

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Number of protons in Xe
Law Incorporation [45]
There are 54 Protons in Xe and 77 Neutrons in Xe.
8 0
3 years ago
What are the science definitions of these
Alecsey [184]

Answer:

Eon-an indefinite and very long period of time, often a period exaggerated for humorous or rhetorical effect.

Era

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geographic isolation-island

Explanation:

3 0
3 years ago
Which of the following is a property of water a. polar molecule b. regulates temperature c.universal solvent d. all of the above
Vladimir [108]
The answer is the letter c
3 0
3 years ago
Read 2 more answers
In the citric acid cycle, malate is dehydrogenated to oxaloacetate in a highly endergonic reaction with a ΔG’o of +30 kJ mol-1:
Doss [256]

Answer :  The value of K_{eq} of this reaction is, 5.51\times 10^{-6}

At equilibrium, [L-malate] > [oxaloacetate]

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

\Delta G^o=-RT\times \ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy  = +30 kJ/mol = +30000 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = 25^oC=273+25=298K

K_{eq}  = equilibrium constant  = ?

The given reaction is:

\text{L-malate}+NAD^+\rightleftharpoons \text{oxaloacetate}+NADH+H^+

\Delta G^o=-RT\times \ln K_{eq}

+30000J/mol=-(8.314J/K.mol)\times (298K)\times \ln K_{eq}

K_{eq}=5.51\times 10^{-6}

Therefore, the value of K_{eq} of this reaction is, 5.51\times 10^{-6}

As, the value of K_{eq} < 1 that means the reaction mixture contains reactants.

At equilibrium, [L-malate] > [oxaloacetate]

7 0
4 years ago
Identify the solute and solvent in each solution:
PolarNik [594]

Answer:

a. 6mL of ethanol and 35mL of water: the solute is ethanol (smallest volume) and the solvent is water (greater volume).

b. 300 g of water containing 8g of NaHCO3: the solute is NaHCO3 (smallest mass) and the solvent is water (greater mass).

c. 0.005L of CO2 and 2L of O2: the solute is CO2 (smallest volume) and the solvent is O2 (greater volume).

Explanation:

Hello there!

In this case, according to the given problem, it turns out possible for us to solve these questions by bearing to mind the fact that in a solution, we can find two substances, solute and solvent, whereas the former is in a smaller proportion in comparison to the latter; in such a way, we infer the following:

a. 6mL of ethanol and 35mL of water: the solute is ethanol (smallest volume) and the solvent is water (greater volume).

b. 300 g of water containing 8g of NaHCO3: the solute is NaHCO3 (smallest mass) and the solvent is water (greater mass).

c. 0.005L of CO2 and 2L of O2: the solute is CO2 (smallest volume) and the solvent is O2 (greater volume).

Regards!

4 0
3 years ago
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