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Marizza181 [45]
3 years ago
9

Batteries (e.g., lead-acid batteries) store chemical energy and convert it to electric energy on demand. Batteries do not store

electric charge or charge carriers. Charge carriers (electrons) enter one terminal of the battery, acquire electrical potential energy, and exit from the other terminal at a lower voltage. Remember the electron has a negative charge! It is convenient to think of positive carriers flowing in the opposite direction, that is, conventional current, and exiting at a higher voltage. (Benjamin Franklin caused this mess!) For a battery rated at 12 V and 350 A-h, determine: a. The rated chemical energy stored in the battery. b. The total charge that can be supplied at the rated voltage.
Physics
1 answer:
castortr0y [4]3 years ago
6 0

Answer:

A battery is a device consisting of one or more electrochemical cells with external connections provided to power electrical devices such as flashlights, smartphones, and electric cars. When a battery is supplying electric power, its positive terminal is the .... Batteries convert chemical energy directly to electrical energy.

Explanation:

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Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

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distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

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Two cars, C and D, travel in the same direction on a long, straight section of highway. During a particular time interval Ato, c
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possibly because the car is running out of gas

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Imagine you have to design a safe, useful device that uses an electric discharge to make your life better. How would you describ
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How is the average kinetic energy of particles related to temperature of a substance?
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Investigators are exploring ways to treat milk for longer shelf life by using pulsed electric fields to destroy bacterial contam
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Answer:

C = 3.77*10⁻¹⁰ F = 377 pF

Q = 1.13*10⁻⁵ C

Explanation:

Given

D = 8.0 cm = 0.08 m

d = 0.95 cm = 0.95*10⁻² m

k = 80.4  (dielectric constant of the milk)

V = 30000 V

C = ?

Q = ?

We can get the capacitance of the system applying the formula

C = k*ε₀*A / d

where

ε₀ = 8.854*10⁻¹² F/m

and   A = π*D²/4 = π*(0.08 m)²/4

⇒  A = 0.00502655 m²

then

C = (80.4)*(8.854*10⁻¹² F/m)*(0.00502655 m²) / (0.95*10⁻² m)

⇒  C = 3.77*10⁻¹⁰ F = 377 pF

Now, we use the following equation in order to obtain the charge on each plate when they are fully charged

Q = C*V

⇒  Q = (3.77*10⁻¹⁰ F)*(30000 V)

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