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Anon25 [30]
3 years ago
9

By how much does the gravitational potential energy of a 54-kg pole vaulter change if her center of mass rises about 4.0 m durin

g the jump
Physics
2 answers:
kodGreya [7K]3 years ago
8 0
<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules. Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>
dexar [7]3 years ago
7 0

Answer:

The gravitational potential energy of pole voulter is 2160\ J.

Explanation:

Given that,

Mass of the pole vaulter, m = 54 kg

Height it rises, h = 4 m

To find,

The gravitational potential energy.

Solution,

We know , gravitational potential energy of an object of mass m and height h is given by m\times g\times h.Here g is acceleration due to gravity=10 m/s^2.

E=m\times g\times h\\=54\times 10 \times 4\ J=2160\ J.

Therefore, the gravitational potential energy of pole voulter is 2160\ J.

Hence, this is the required solution.

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Equations to use: v= λ ∙ f v=d/t
Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

f=\frac{v}{2L}

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

v=\frac{d}{t}

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

t = 3 s is the time taken

Re-arranging the formula and substituting the numbers into it, we find:

d=vt=(6,000 m/s)(3 s)=18,000 m

3 0
3 years ago
As frequency increases, what happens to the tone (or pitch) of a sound? Which option is it?
icang [17]

Answer:

gets higher

Explanation:

There are videos that show the range of human hearing.  If you would play the video, you would notice that if the frequency increases, the pitch would also increase.

3 0
3 years ago
Please explain how to solve 17 and 18
andriy [413]

Answer:

17. h = l − l cos θ

18. 1.40 m

Explanation:

Let's call d the height of the triangle.  We can then say:

h = l − d

Using trig, we can write d in terms of l and θ:

d = l cos θ

h = l − l cos θ

If l = 6 m and l cos θ = 40°:

h = 6 − 6 cos 40

h ≈ 1.40

3 0
2 years ago
HELP PLEASE HERE IS THE IMAGE
kari74 [83]

Answer:

I am pretty sure it's E because it splits through every layer

3 0
3 years ago
Read 2 more answers
Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 x 10^4 Pa. If
frez [133]

Answer:

p2 = 9.8×10^4 Pa

Explanation:

Total pressure is constant and PT = P = 1/2×ρ×v^2  

So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2

from continuity we have ρ×A1×v1 = ρ×A2×v2  

v2 = v1×A1/A2  

and  

r2 = 2×r1

then:

A2 = 4×A1  

so,

v2 = (v1)/4  

then:

p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2  

p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)  

     = 9.75×10^4 Pa

    = 9.8×10^4 Pa

Therefore, the pressure in the wider section is 9.8×10^4 Pa

5 0
3 years ago
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