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Anon25 [30]
3 years ago
9

By how much does the gravitational potential energy of a 54-kg pole vaulter change if her center of mass rises about 4.0 m durin

g the jump
Physics
2 answers:
kodGreya [7K]3 years ago
8 0
<span>the gravational potential energy of anything on the ground is zero. When calculating potential energy you take height in meters and multiply it by the mass of the object in kilograms and the acceleration of gravity to get a new unit called Joules. Any object at ground level has a potential energy of zero newtons becuase anything multiplied by zero is zero. An object with mass of 54 kg, 4 meters above the ground has a gravitatinal potential energy of 2116.8 Joules.</span>
dexar [7]3 years ago
7 0

Answer:

The gravitational potential energy of pole voulter is 2160\ J.

Explanation:

Given that,

Mass of the pole vaulter, m = 54 kg

Height it rises, h = 4 m

To find,

The gravitational potential energy.

Solution,

We know , gravitational potential energy of an object of mass m and height h is given by m\times g\times h.Here g is acceleration due to gravity=10 m/s^2.

E=m\times g\times h\\=54\times 10 \times 4\ J=2160\ J.

Therefore, the gravitational potential energy of pole voulter is 2160\ J.

Hence, this is the required solution.

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A hovering mosquito is hit by a raindrop that is 50 times as massive and falling at 8.4 m/s, a typical raindrop speed. How fast
kenny6666 [7]

The final velocity after the collision is 8.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, if we consider the system to be isolated (=no external unbalanced forces), the total momentum of the raindrop+mosquito must be conserved before and after the collision.

If the collision is perfectly inelastic, moreover, the raindrop and the mosquito stick together and travel at the same velocity v after the collision.

Mathematically:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 is the mass of the first mosquito

u_1 = 0 is the initial velocity of the mosquito

m_2 = 50 m_1 is the mass of the raindrop

u_2 = 8.4 m/s is the initial velocity of the raindrop

v is the final combined velocity of the raindrop+mosquito

Re-arranging the equation and substituting, we find:  

m_1 u_1 + 50 m_1 u_2 = (m_1 + 50 m_1) v\\50 m_1 u_2 = 51 m_1 v\\50 u_2 = 51 v\\v=\frac{50}{51}u_2 = \frac{50}{51}(8.4)=8.2 m/s

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

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#LearnwithBrainly

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3 years ago
Time measurements from a stopwatch are not precise. Why not ?
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Human error (average human reaction time is .2 seconds)
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How do you calculate acceleration
AfilCa [17]
A=f/m
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7 0
3 years ago
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A force of 250 N is applied to a 1 kg softball when struck with a bat. what is the acceleration
My name is Ann [436]
A=f/m
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8 0
3 years ago
hii! i need answers for both of these! this is due tomorrow and i want to get it done so i can finish all my other work, thank y
d1i1m1o1n [39]

Answer:

The mass and velocity for kinetic energy. Potential Energy: How high an object is and the mass in kilograms or it is the weight in and how high an object is. There are two formulas to calculate potential energy, but the one with grams is used more often.

Explanation:

Hope this helps!

5 0
3 years ago
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