Question

what is the frequency of the photon emitted by a hydrogen atom when its electron drops from the n = 6 to n = 4 energy level?

Answer 1

The frequency of the photon emitted by a hydrogen atom is   $26.2*10^-^4 hz$

What are Photons?

A particle representing a quantum of light or other electromagnetic radiation. A photon carries energy proportional to the radiation frequency but has zero rest mass.

In the case of light, the frequency, symbolized by the Greek letter nu (ν), of any wave equals the speed of light, c, divided by the wavelength λ:

v = c/λ

Since the wavelength λ is in the bottom of the fraction, the frequency is inversely proportional to the wavelength.

v = c/λ

v= $\frac{3*10^8}{434*10^-^9} = 6.91*10^1^4 Hz$

By using Rydberg's formula,

1/λ $= Rz^2(\frac{1}{n_1^2} - \frac{1}{n_2^2})$

1/λ = $109677 *(\frac{1}{4^2} - \frac{1}{6^2}) = 3808.22 cm^-^1$

λ  = $26.2*10^-^4 hz$

$26.2*10^-^4 hz$ is  frequency of the photon emitted by a hydrogen atom.

Learn more about Photons here:brainly.com/question/20912241

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