<em><u>Answer </u></em><em><u>:</u></em><em><u> </u></em><em><u>M</u></em><em><u>etal containers</u></em><em><u> </u></em><em><u>are</u></em><em><u> not</u></em><em><u> </u></em><em><u> </u></em><em><u>used for storing acid</u></em><em><u> because most of the time acid reacts with almost every metal and produces </u></em><em><u>salts</u></em><em><u> or oxid</u></em><em><u>e</u></em><em><u>s</u></em><em><u> </u></em><em><u>which alters the acid characteristics making it useless</u></em><em><u> </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
1.20 M
Explanation:
Convert grams of Na₂CO₃ to moles. (50.84 g)/(105.99 g/mol) = 0.4797 mol
Molarity is (moles of solute)/(liters of solvent) = (0.4797 mol)/(0.400 L) = 1.20 M
Answer:
Explanation:
The given pH = 8.55
Unknown:
[H₃O⁺] = ?
[OH⁻] = ?
In order to find these unknowns we must first establish some relationship.
pH = -log[H₃O⁺]
8.55 = -log[H₃O⁺]
[H₃O⁺] = inverse log₁₀(-8.55) = 2.82 x 10⁻⁹moldm⁻³
To find the [OH⁻],
pH + pOH = 14
pOH = 14 - pH = 14 - 8.55
pOH = 5.45
pOH = -log[OH⁻]
[OH⁻] = inverse log₁₀ (-5.45) = 3.55 x 10⁻⁶moldm⁻³
The solution is basic because it has more concentration of OH⁻ ions compared to H⁺ ions.
The answer is 100%
let me know if you want an explanation
If its sodium it would have 11 electrons
