Please help and I will help u
Given:
'a' and 'b' are the intercepts made by a straight-line with the co-
ordinate axes.
3a = b and the line pass through the point (1, 3).
To find:
The equation of the line.
Solution:
The intercept form of a line is
...(i)
where, a is x-intercept and b is y-intercept.
We have, 3a=b.
...(ii)
The line pass through the point (1, 3). So, putting x=1 and y=3, we get



Multiply both sides by a.

The value of a is 2. So, x-intercept is 2.
Putting a=2 in
, we get


The value of b is 6. So, y-intercept is 6.
Putting a=2 and b=6 in (i), we get

Therefore, the equation of the required line in intercept form is
.
Answer: i dont really know if im right but here! :L
Step-by-step explanation: Now, say G is an Abelian group, finitely generated from generator In this sense abelian groups are “more interesting” than vector spaces. and in the table below, the second last column is the identity, while the last column is cyclic of order 4, with 9g the generator
The eight should be in parentheses but the eight turns into a positive making the answer 4
hope this helps!