Answer:
The answer is
<h2>4 hrs</h2>
Explanation:
To find the time taken we use the formula
where
d is the distance covered
v is the velocity
t is the time
From the question
d = 1200 miles
v = 300 mi/hr
We have
We have the final answer as
<h3>4 hrs</h3>
Hope this helps you
Explanation:
a. moving a 145 kg aluminum sculpture across a horizontal steel platform
b. pulling a 15 kg steel sword across a horizontal steel shield
c. pushing a 250 kg wood bed on a horizontal wood floor
d. sliding a 0.55 kg glass amulet on a horizontal glass display case
Answer:
1. The automobile is traveling due east and is speeding up.
2. The car is traveling due east and is is slowing down.
3. The automobile is traveling due east at a constant speed.
4. The car is traveling due west and is slowing down.
5. The automobile is traveling due west and is speeding up.
6. The automobile is traveling due west at a constant speed.
7. The automobile is accelerating due east from rest.
8. The automobile is accelerating due west from rest.
Explanation:
The key to understanding this is:
When the acceleration and initial velocity of the automobile have the same sign (positive or negative) then the automobile is speeding up. Explained further, if acceleration and the initial velocity are both positive or they are both negative the automobile is speeding up but whenever they have opposite signs (that is acceleration is positive and initial velocity is negative or vice versa) the automobile is slowing down. When the acceleration is zero the automobile is maintaining a unform motion at a constant speed (the speed is not changing with time). The + or - sign indicates the direction of travel. In this case east is + and west is -. It is my pleasure answering this question. I hope you find it helpful. Thank you.
Answer:
v = 25 m / s
Explanation:
For this exercise we use the relations and kinematics
first part, the train accelerates from v₀ = 7.0 m/s to 13 m/s in a time t = 8.0 s
v = v₀ + a t
a = 
a = 
a = 0.75 m / s²
second part. Accelerate again for t = 16 s
v = v₁ + a t
for this interval the initial velocity is v₁ = 13 m / s
v = 13 + 0.75 16
v = 25 m / s
