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Cloud [144]
3 years ago
11

A 15-kilogram cart is at rest on a horizontal

Physics
1 answer:
Sergio [31]3 years ago
6 0
The most likely answer to this problem would be (1) more mass and more inertia.

A 15-kilogram cart at rest and a 5-kilogram box would make up a 20-kilogram cart and box that is at rest on a horizontal surface. The mass changed into something more, of course, as a result of combining the two object into one and by combining the two objects' mass, the inertia that it previously possessed as a cart by itself was increased when the inertia of the box was also combined to the cart.
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A car with a constant velocity of 22 m/s is driven for 6.8 s. How far did it travel? (V =A d/AT)
SVEN [57.7K]

Answer: 150 m

Explanation:

velocity = 22 m/s

t = 6.8 s

velocity = \frac{distance}{time}

distance = velocity × time

= 22 × 6.8

= 149.6 m

≈ 150 m

option C

6 0
3 years ago
Location C is 0.02 m from a small sphere which has a charge of 3 nanocoulombs uniformly distributed on its surface. Location D i
kkurt [141]

The change in potential along a path from C to D due to a small charged sphere is 900 V.

Given:

Charge, Q = 3 nC = 3 × 10⁻⁹ C

Distance between the sphere and point C, r₁ = 0.02 m

Distance between the sphere and point D, r₂ = 0.06 m

Calculation:

We know that the electric potential is given as:

V = k Q/r   - (1)

where, V is the electric potential

            k is Coulomb's force constant

            Qis the charge on the  sphere

            r is the  separation distance

The electric potential at point C due to charged sphere can be given as:

V₁ = k Q/r₁

   = (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.02 m)]

   = 1350 V

The electric potential at point D due to charged sphere can be given as:

V₂ = k Q/r₂

   = (9×10⁹ Nm²/C²) [(3 × 10⁻⁹ C)/(0.06 m)]

   = 450 V

Now, the change in potential along the path from C to D can be calculated as:

ΔV = V₂ - V₁

     = 450 V - 1350 V

     = -900 V

The negative sign indicates that the work is done against the electric field in moving the charge from C to D.

Therefore, the change in potential along a path from C to D is 900 V against the direction of the electric field.

Learn more about the electric potential here:

<u>brainly.com/question/12645463</u>

#SPJ4

8 0
1 year ago
Read 2 more answers
a roller coaster is at the top of a hill and rolls to the top of a lower hill.If mechanical energy is conserved,on the top of wh
pychu [463]
Hello!!

Here we have a simple matter of conservation of energy. ME=PE+KE.

At point A we have PE=mgh and KE=1/2mv^2. At point A all we have is PE since the coaster isn’t rolling yet. But by conservation of energy, we know that it will have enough energy to roll down and get to and equal height on another hill. Providing we are neglecting friction and drag and resistance forces which we are in this case. So we can conclude that the KE will be greater at Point B since ME=PE+KE and for ME to remain the same and we know the PE is less on lower hill, so we can conclude that KE on lower hill is greater to keep ME the same and have conservation of energy.

Hope this helps you understand the concept!! Any questions please just ask!! Thank you so much!!
7 0
3 years ago
Find the hiker’s gravitational potential energy if the cliff is 60m high
Furkat [3]

Answer:

Potential energy is U=mgh

Explanation:

The potential energy depends on the mass, the acceleration of gravity g and the height at which the object or person is.

Potential energy  U=mgh

In this case we would need to know the exact mass of the hiker in order to calculate the potential energy.

But we know the values of g and h

g=9.81m/s^2

h=60m

So, the potential energy

U=m(9.81m/s^2)(60m)\\\\U=588.6*m

m is the mass of the hiker, wich is not in the description of the problem.

4 0
2 years ago
17. (16 pts) You set up a two-slit experiment with a laser that produces light with a
Natali [406]

when the two waves interfere with eachother to make a dark spot the periodic difference of the two waves is π . the wave length for 2π is 600nm

. ie. for π difference it is 300nm

4 0
3 years ago
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