Answer:
Volume of secret cavity = 4 x 10⁻⁶m³
Explanation:
The weight of the sculpture in air is 15.76 N
Mass of the sculpture = 1.61 kg
Mass = Volume x Density
1.61 = V x 8470
Volume of brass =1.90 x 10⁻⁴ m³
When it is submerged in water, the weight is 13.86 N.
That is
Weight of sculpture - Weight of water displaced = 13.86 N
15.76 - Weight of water displaced = 13.86
Weight of water displaced = 1.9 N
Mass of water displaced = 0.194 kg
Mass = Volume x Density
0.194 = V x 1000
Volume of water displaced =1.94 x 10⁻⁴ m³
Volume of secret cavity = Volume of water displaced - Volume of brass material
Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³
The fundamental frequency of the open pipe A
Length 'L₀' is, f₀ = U/2L₀ = 340 H₂
the speed of sound in air V= 343m/s
∴343/2L₀ = 340 → length L₀ = 343/2 ×340 = 0.5044 = 50.44
The third harmonic of closed pipe 'B' is
F3₀ = 3V/4LC
The second harmonic of open pipe 'A' is
f2₀ = 2V/2L₀
∴ 3V/4LC = 2V/2L →L₀ = 3L₀/4
⇒ The length of closed pipe B is
Lc = 37.83cm
I think the correct answer from the choices listed above is option C. The formula that would represent the speed of the Toyota would be <span>T+10 mph= 60 mph. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
note-Unlike the planetary model, our model view is that the electrons move around the nucleus in an electron cloud. Modern atomic theory states that the atom is a diffuse cloud surrounding a small, dense nucleus. Identify which particle is in the nucleus. note-Neutron is a particle in the nucleus.
Answer:
26.822 m/s
Explanation:
60 mi/hr * 5280 ft/mile * 1 hr / 3600 sec * 12 in / foot * 1 meter / 39.37 in = <u>26.822 m/s</u>
