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2 years ago

In 'coin on card' experiment a smooth card is used.

Physics

2 answers:

liq [111]2 years ago

8 0

In three words I can sum up everything I’ve learned about life: it goes on. ― Robert Frost

KIM [24]2 years ago

5 0

Answer:

In coin card experiment smooth card is used so that the card can slide easily from glass

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How far will a man travel in 15 min driving his car down the highway at an average speed of 24 m/?s

emmasim [6.3K]

Answer:

21.6 km

Explanation:

15×60×24 = 21600 m

$\frac{21600}{1000}$ = 21.6 km

7 0

2 years ago

You throw a 3.00 N rock vertically into the air from ground level. You observe that when it is 16.0 m above the ground, it is tr

Morgarella [4.7K]

Answer:

The final speed of the stone as it lift the ground is 23.86 m/s.

Explanation:

Given that,

Force acting on the rock, F = 3 N

Distance, d = 16 m

Initial speed of the stone, u = 22 m/s

We need to find the rock's speed just as it left the ground. It can be calculated using work energy theorem as :

$W=\Delta E\\\\W=\dfrac{1}{2}m(v^2-u^2)\\\\Fd=\dfrac{1}{2}m(v^2-u^2)\\\\v^2=\dfrac{2Fd}{m}+u^2\\\\v^2=\dfrac{2mgd}{m}+u^2\\\\v^2=2\times 9.8\times 16+(16)^2\\\\v=23.86\ m/s$

So, the final speed of the stone as it lift the ground is 23.86 m/s.

4 0

2 years ago

My Notes (a) A 41 Ω resistor is connected in series with a 6 µF capacitor and a battery. What is the maximum charge to which thi

Lilit [14]

Explanation:

The give data is as follows.

C = 6 $\mu F$ = $6 \times 10^{-6} F$

V = 6 V

Now, we know that the relation between charge, voltage and capacitor for series combination is as follows.

Q = CV

= $6 \times 10^{-6} F \times 6 V$

= $36 \times 10^{-6} C$

or, = 36 $\mu C$

Thus, we can conclude that maximum charge of the given capacitor is 36 $\mu C$ .

8 0

2 years ago

Read 2 more answers

A machine exerts a 100 N force to the right over a 5.00 meter length in 4.00 seconds. Calculate the power output of this machine

bixtya [17]

125 W is the power output of this machine.

Answer:

Explanation:

Power is defined as the amount of work done on the system to move that system from its original state within the given time interval. So it can be determined by the ratio of work done with time interval. As work done is the measure of force required to move a system to a certain distance. Work done is calculated as product of force with displacement.

So in the present case, the force is given as 100 N, the displacement is given as 5 m and the time is given as 4 s, then power is

$Power = \frac{Work done}{Time}$