Answer:
sned me short notes of Physics of all branches (post graduation level) thanks
+923466867221
Explanation:
Answer: Idk I think I forgot
Explanation:
efficiency=work output/work input×100
since it exhausts(use up)3000j of heat that's the work input and the 1500j is the work input
efficiency=1500/3000×100
=50%
Given Information:
Initial speed = u = 3.21 yards/s
Acceleration = α = 1.71 yards/s²
Final speed = v = 7.54 yards/s
Required Information:
Distance = s = ?
Answer:
Distance = s = 13.61
Explanation:
We are given the speeds and acceleration of the runner and we want to find out how much distance he covered before being tackled.
We know from the equations of motion,
v² = u² + 2αs
Where u is the initial speed of the runner, v is the final speed of the runner, α is the acceleration of the runner and s is the distance traveled by the runner.
Re-arranging the above equation for distance yields,
2αs = v² - u²
s = (v² - u²)/2α
s = (7.54² - 3.21²)/2×1.71
s = 46.55/3.42
s = 13.61 yards
Therefore, the runner traveled a distance of 13.61 yards before being tackled.
<u>Answer:</u>
Both the objects A and B will have the same acceleration.
<u>Explanation
:</u>
The objects will have the same acceleration as both are under free fall condition. When objects are under the free fall condition, the only force that acts on the object is its weight.
Weight is the force acting on a body of some mass, and the formula for finding the weight of a body is- Weight = mass × acceleration due to gravity(g).
Therefore, here the different weight is due to the difference masses of both bodies, and not due to the different acceleration values.
