Answer:
Explanation:
A. Using
Sinစ= y/ L = 0.013/2.7= 0.00481
စ=0.28°
B.here we use
Alpha= πsinစa/lambda
= π x (0.0351)sin(0.28)/588E-9m
= 9.1*10^-2rad
C.we use
I(စ)/Im= (sin alpha/alpha) ²
So
{= (sin0.091/0.091)²
= 3*10^-4
solution:
radius of steel ball(r)=5cm=0.05m
density of ball =8000kgm
terminal velocity(v)=25m/s^2
density of air( d) =1.29 kgm
now
volume of ball(V)=4/3pir^3=1.33×3.14×0.05^3=0.00052 m^3
density of ball= mass of ball/Volume of ball
or, 8000=m/0.00052
or, m=4.16 kg
weight of the ball (W)= mg=4.16×10=41.6 N
viscous force(F)=6 × pi × eta × r × v
=6×3.14×eta×0.05×25
=23.55×eta
To attain the terminal velocity,
Fiscous force=Weight
or, 23.55× eta = 41.6
or, eta = 1.76
whete eta is the coefficient of viscosity.
Answer:
My mom always told me he was just there
Explanation:
No...........................................................................Work for them urself
Answer:
1. What type of wave is sound?
2.Does sound need a medium to travel through?
3. What are the properties of sound waves?
Explanation:
1. The type of waves sound are is mechanical waves.
2. Sound needs a solid, liquid or gas (material medium) to travel through.
3. I believe they are wavelength, amplitude, frequency, time period and velocity.
I apologize if it is incorrect-
I hope it helps! Have a great day!
Anygays-
